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anonymous

  • one year ago

1.)Find the volume of the given prism. Round to the nearest tenth if necessary. http://assets.openstudy.com/updates/attachments/5101d810e4b03186c3f87d4c-khart-1359075406633-problem1.jpg My answer: 265.1 cm^3. Is that correct? 2.) Find the volume of the given prism. Round to the nearest tenth if necessary. http://assets.openstudy.com/updates/attachments/5101d810e4b03186c3f87d4c-khart-1359075472438-problem2.jpg my answer: 1,756.3yd^3. Is that correct?

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  1. anonymous
    • one year ago
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    @nincompoop @dan815

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    • one year ago
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    • one year ago
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    • one year ago
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    @mathmate @mathmath333 @jagr2713 @ganeshie8

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    • one year ago
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    • one year ago
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    • one year ago
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    • one year ago
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  10. anonymous
    • one year ago
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    @mathmate Can you stay and not leave like everyone else?

  11. anonymous
    • one year ago
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    Everyone always comes in and then leaves...its been like an hour and a half

  12. mathmate
    • one year ago
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    I'll stay!

  13. anonymous
    • one year ago
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    okay thank you

  14. mathmate
    • one year ago
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    Can you explain to me how you got your first answer?

  15. anonymous
    • one year ago
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    Sure.

  16. anonymous
    • one year ago
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    rectangle is LxWxH (Length*Width*Height) length=12.1cm width=5.3cm height=4.2cm ------------ LxWxH (12.1cm)*(5.3cm)*(4.2cm) 269.346cm^3

  17. mathmate
    • one year ago
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    Yes, this is correct. But not 265.1 that you posted earlier! lol

  18. mathmate
    • one year ago
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    Now for the second one, can you explain how you got your answer?

  19. mathmate
    • one year ago
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    oh wait, you're supposed to round the answer to the nearest tenth. Hope you did that!

  20. anonymous
    • one year ago
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    I did that and....so I did it correctly?

  21. anonymous
    • one year ago
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    269.3 cm^3?

  22. mathmate
    • one year ago
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    Yes, then 269.3 is the answer for the first. Agreed. Now can you tell me the story about the second one?

  23. mathmate
    • one year ago
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    * cm^3, yes.

  24. mathmate
    • one year ago
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    working on the second one?

  25. anonymous
    • one year ago
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    Are you asking me? I am not.

  26. mathmate
    • one year ago
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    "Now can you tell me the story about the second one?"

  27. mathmate
    • one year ago
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    sorry, gtg!

  28. mathmate
    • one year ago
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    I promised to stay and I stayed. I go when the asker of the question stops participating. I am sorry but cannot sit and wait when others need help.

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