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Complex zeroes always occur as conjugates
so if 1 - 2i is a zero of the function then so is 1 + 2i

yeah i get that but that isnt the answer is it?

well you can find another zero by dividing the function by
(x - (1 + 2i)(x - (1 - 2i)

see thats what i dont know how to do

= (x^2 + 5)
use long or synthetic division

how do i do that though

i dont know how to dived with i's in it

i only know know to dive if theres no imaginary munbers

no theres no i's its f(x) divided by x^2 + 5

so the whole equation divided by x^2+5 and thats it

how am i supposed to do that synthetically?

do i put -5 in the window

im just not understanding how to get the 2 real number answers bc i dont know how to divide it

yea i'm trying to divide it now on paper but i cant get it to divide exactly

No it doesnt divide exactly There might be a mistake in the question.

I'm not very good at synthetic division but that wont work either - if long division hasn't

i figured it out just now thank you so much i got +/- i and im hoping thats right

yeah idk i just kind of did it a different way but thank you for your help i appreciate it

yw