Descartes' Rule of Signs: 2x^4-7x^3+3x^2+8x-4
This equation shows that there would be either 3 positive roots, or 1 positive root, but my answer and the answer at the back of my textbook say that there are only two positive roots; 1/2, and 2.
The Descartes' Rule of Signs says that the number of positive roots is either equal to the number of variations in sign or is less than that by an even whole number. Why does that not apply to this equation?

See more answers at brainly.com

what are the number of variations in your positive setup?

I was thinking that it was 3 variations

2x^4 -7x^3 +3x^2 +8x -4
| | |
0 1 2 3
i count 3 as well

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.