calculusxy
  • calculusxy
MEDAL!!! The sum of two numbers is 825. Dividing the larger number by the smaller number yields 8 with a remainder of 15. What are the two numbers? (You can solve this using a system of equations)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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calculusxy
  • calculusxy
@amistre64 @triciaal
amistre64
  • amistre64
setup your system
triciaal
  • triciaal
go step by step pick your 2 numbers decide which is larger sum is what you get when you add when you divide the original is the quotient * divisor + remainder

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triciaal
  • triciaal
|dw:1438640533271:dw|
calculusxy
  • calculusxy
x = larger number y = smaller number x + y = 825 y / x = 8 R 15
calculusxy
  • calculusxy
@triciaal Is this how I am supposed to start?
calculusxy
  • calculusxy
@Nnesha
amistre64
  • amistre64
l + s = 825 yes l/s = 8 + 15/s should suffice
amistre64
  • amistre64
l=8s+15 simplifies the 2nd
calculusxy
  • calculusxy
\[x + y = 825\] (x is larger) \[8y + 15 = x\] I just did the inverse of what it said. Since the larger number would have to be divided, and then a remainder of 15.
calculusxy
  • calculusxy
\[(8y + 15) + y = 825\] \[9 y + 15 = 825\] \[9y = 810\] \[ y = 90\] to find out x: \[825 =- 90 = 735 = x\]
calculusxy
  • calculusxy
Is that correct?
amistre64
  • amistre64
90 and 735 work for me yes
calculusxy
  • calculusxy
thank you!!
calculusxy
  • calculusxy
I have another question. Can you please help me on that as well?
amistre64
  • amistre64
maybe
calculusxy
  • calculusxy
okay one moment
calculusxy
  • calculusxy
calculusxy
  • calculusxy
What is the x- intercept? A. -3
calculusxy
  • calculusxy
Am i correct?
amistre64
  • amistre64
it intercepts the x axis .. at x=-3 yes
calculusxy
  • calculusxy
thank you!!!!!!!!
amistre64
  • amistre64
but all i see is a picture and no real question attached to it
triciaal
  • triciaal
this is not a real parabola if the vertex is at -3 then y cannot be 3 and -2 what is the complete question?
triciaal
  • triciaal
|dw:1438642939447:dw|

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