I got an answer for this trig problem and I want to see if it is correct

- anonymous

I got an answer for this trig problem and I want to see if it is correct

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- katieb

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- anonymous

##### 1 Attachment

- anonymous

I know the answer is either approximately 50.3m or approximately 39.3m, but I do not know which one it is

- anonymous

@jim_thompson5910

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## More answers

- IrishBoy123

did you draw the picture? rough sketch will suffice

- anonymous

i did

- IrishBoy123

|dw:1438642173189:dw|

- anonymous

|dw:1438642164202:dw|

- anonymous

Here is what I did

##### 1 Attachment

- anonymous

@mathstudent55

- anonymous

@IrishBoy123 did I solve the problem correctly

- IrishBoy123

why did you not use cos 43 ?

- IrishBoy123

https://www.mathsisfun.com/algebra/trig-cosine-law.html

- anonymous

wait why would it be cos 43

- IrishBoy123

well look at the link
just asking

- anonymous

I guess that it is right I think

- amistre64

law of cosine is fine, but i dont know how to read the bearings ...

- IrishBoy123

|dw:1438642650401:dw|

- anonymous

So my new equation is \[d=\sqrt{30^2+34^2-2(30)(24)(\cos(43}))\]

- IrishBoy123

yes
but that has to make sense to you....
again
http://mathworld.wolfram.com/LawofCosines.html

- IrishBoy123

and typo (!) : \(34^2 -> 24^2\)

- anonymous

Your graph made better sense than the link, thank you though, therefore my new anser should be, 20.6m

- IrishBoy123

if **you** are happy with it
in the attached diagram we can say - from Law of Cosines - that
\( \large a^2 = b^2 + c^2 - 2 b c\ cos A\)
|dw:1438643019135:dw|

- anonymous

ok so is my new anser 20.6m

- IrishBoy123

|dw:1438643119009:dw|
and
\(b^2 = a^2 + c^2 - 2ac \ cos B\)

- IrishBoy123

it is Pythagoreas expanded
|dw:1438643242132:dw|
so
\(\large c^2 = a^2 + b^2 - 2ab \ cos C\)

- anonymous

ok, but can you confirm that I have the right answer

- IrishBoy123

and yes i seem to agree with you

- anonymous

ok so the answer to my original problem is20.6

- IrishBoy123

i should think so

- IrishBoy123

|dw:1438643502160:dw|
look at this, where C = 90
\(c^2 = a^2 + b^2 - 2ab \ cos C = a^2 + b^2 - 2ab \ (0)\)
\(c^2 = a^2 + b^2\)

- anonymous

Can you help me with a simpler problem that I also dont know whether I got right or wrong

- anonymous

@jdoe0001

- jdoe0001

repost anew, thus more eyes :)

- jdoe0001

20.6 is correct btw

- anonymous

ok

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