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anonymous

  • one year ago

-4(x + 10) - 6 = -3(x - 2). I need help solving this please.

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  1. anonymous
    • one year ago
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    do cross multiply

  2. anonymous
    • one year ago
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    |dw:1438645079753:dw|

  3. anonymous
    • one year ago
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    Once you cross multiply, you can combine like terms.

  4. anonymous
    • one year ago
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    so then it would be -40 times -6 = 2 times -6? or something like that

  5. anonymous
    • one year ago
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    sorry im having alot of trouble focusing cri

  6. anonymous
    • one year ago
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    \[-4(x+10)-6=-3(x-2)\]\[-4x-40-6=-3x+6\]

  7. anonymous
    • one year ago
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    add like terma as in the x variable

  8. anonymous
    • one year ago
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    terms**

  9. anonymous
    • one year ago
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    \[-4x-46=-3x+6\]

  10. anonymous
    • one year ago
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    Now try to get the like terms grouped together.

  11. anonymous
    • one year ago
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    Are you getting it so far ? @misty_fox

  12. anonymous
    • one year ago
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    Yes im just trying writing it down on paper, one sec

  13. anonymous
    • one year ago
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    -46?

  14. anonymous
    • one year ago
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    Ya. -40-6 = -46. I combined those numbers in the second step.

  15. anonymous
    • one year ago
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    So what's next ? @misty_fox

  16. anonymous
    • one year ago
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    would that be the final answer tho? cuz that is one of the options

  17. anonymous
    • one year ago
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    You would have to bring the x terms on one side of the equation after that 3rd step. Do you know how to do that?

  18. anonymous
    • one year ago
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    Yea i did that and i got -47 but its closest to -46 and i might have did it wrong but idk

  19. anonymous
    • one year ago
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    \[-4x-46=-3x+6\]\[-4x+3x=46+6\]\[-x=52\]\[x=-52\]

  20. anonymous
    • one year ago
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    Is -52 one of the answer choices?

  21. anonymous
    • one year ago
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    I just got that too ^^^

  22. anonymous
    • one year ago
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    Okay great! :)

  23. anonymous
    • one year ago
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    Did you get that @misty_fox?

  24. anonymous
    • one year ago
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    Yes sorry i was afk, thank you very much! :)

  25. anonymous
    • one year ago
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    You're welcome!

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