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anonymous

  • one year ago

Just want someone to check over my answer! How many different ways can the letters of the word RIVAL be scrambled so that the 2 vowels can be together?

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  1. anonymous
    • one year ago
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    nvm it's \[6! / 2!3!\]

  2. anonymous
    • one year ago
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    = 60?

  3. mathstudent55
    • one year ago
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    Think of the letters AI being 1 letter. How many ways can you arrange the letters R, V, L, AI? Then think of the letters IA being 1 letter. How many ways can you arrange R, V, L, IA? Then add the two results. |dw:1438646050051:dw|

  4. anonymous
    • one year ago
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    im so confused.. so would i just do 4!?

  5. mathstudent55
    • one year ago
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    Think of the simple problem: How many ways can you arrange the letters of the "word" RLVX

  6. mathstudent55
    • one year ago
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    In this case, the answer would be simply the counting principle, 4!, right? Your case is similar to this case. Since the two letters A and I must be together, they count as a unit. Call the letters A and I together just X. How many ways can you arrange the letters of the "word" RLVX? Answer: 4! Since AI can be together as AI or as IA, you need to do the counting principle for each way of grouping A and I, so you get 2 * 4!.

  7. anonymous
    • one year ago
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    ahah aight thank youuu

  8. mathstudent55
    • one year ago
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    You're welcome.

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