Solve the compound inequality 6b < 24 or 4b + 12 > 4. b < 4 or b > −2 b < 4 or b > 4 b < 4 or b > 2 b > 4 or b < −2

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Solve the compound inequality 6b < 24 or 4b + 12 > 4. b < 4 or b > −2 b < 4 or b > 4 b < 4 or b > 2 b > 4 or b < −2

Mathematics
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Focus on just 6b < 24 for now. How would you isolate b here?
multiply 6 on both sides? im new to this so idk
|dw:1438647266814:dw|

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Other answers:

the 6b means "6 times b" we need to undo the multiplication so we divide both sides by 6 to isolate b |dw:1438647301431:dw|
4
the '6's on the left side divide to 1 and cancel out more or less the 24/6 on the right side becomes 4 |dw:1438647326597:dw|
now we solve 4b + 12 > 4 for b
what's the first step?
4 + 12 ?
you have to follow PEMDAS in reverse 4b + 12 means 4*b + 12 the first thing we undo is the +12
how do you undo the +12?
idk :(
what's the opposite of addition?
subtraction
subtract 12 from both sides |dw:1438647623112:dw|
|dw:1438647650724:dw|
what does 4-12 become?
-8
good
we now have 4b > -8
now what?
hmmmm
hint: look back at how we solved 6b < 24
take 4 from both sides ?
4b means "4 times b" what must you do to both sides to undo the multiplication of 4?
divide by 4
dividing both sides of 4b > -8 by 4 gives you what?
1 and -2
so my answer would be b> 4 or b < -2 right ?
when we solved 6b < 24, what did we get?
oops, we got B < 4
yes
so B < 4 or B > -2
correct
gahhhhhh thank you !!
you're welcome

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