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anonymous

  • one year ago

Lol i still can't get this halp 4(x + 1) = 4x + 4. 5 = 4 x 2 + 4 5 = 12

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  1. anonymous
    • one year ago
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    okay so i assume you just want to solve for x in the function 4(x + 1) = 4x + 4. right?

  2. anonymous
    • one year ago
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    oops the 2 second lines are my work that i messed up on the problem is 4(x+1) = 4x + 4

  3. anonymous
    • one year ago
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    Okay do you remember how to distribute the 4 into (x+1)?

  4. anonymous
    • one year ago
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    the options for it are no solution 0 all real numbers 1

  5. anonymous
    • one year ago
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    It's like taking 4 and multiplying x and +1 separately. Just think of it like that when you get started.

  6. anonymous
    • one year ago
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    Did you get that @misty_fox?

  7. anonymous
    • one year ago
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    4(x+1) = 4x + 4 we start of by distributing 4(x+1) = 4(x + 1) and here you can see that everything cancels out which usually means the solution is all real numbers to make sure you can plug in both 0 and 1 just to make sure and sure enough they both work

  8. anonymous
    • one year ago
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    woops ment to say factoring not distributing but you can distribute too and you'd still get to equal functions on either side

  9. anonymous
    • one year ago
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    Yes watchpencilpaper is right! :)

  10. mathstudent55
    • one year ago
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    |dw:1438647617935:dw|

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spraguer (Moderator)
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