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anonymous
 one year ago
Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.
Which of these could be a step to prove that BC^2 = AB^2 + AC^2?
By the cross product property, AB^2 = BC
multiplied by BD.
By the cross product property, AC^2 = BC multiplied by BD.
By the cross product property, AC^2 = BC multiplied by AD.
By the cross product property, AB^2 = BC multiplied by AD.
anonymous
 one year ago
Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC^2 = AB^2 + AC^2? By the cross product property, AB^2 = BC multiplied by BD. By the cross product property, AC^2 = BC multiplied by BD. By the cross product property, AC^2 = BC multiplied by AD. By the cross product property, AB^2 = BC multiplied by AD.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can anybody please help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Hero @triciaal @pooja195
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