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anonymous

  • one year ago

What are the foci of the following graph? how do i find that?

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  1. anonymous
    • one year ago
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  2. Loser66
    • one year ago
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    a=? b=? c^2=a^2-b^2

  3. Loser66
    • one year ago
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    |dw:1438653300551:dw|

  4. anonymous
    • one year ago
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    The foic lie on the line called the major. This ellipse major is on the x axis. The equation of this ellipse is \( \huge \frac{x^2}{36} +\frac{y^2}{4} = 1 \) The foci is (c, 0) and (-c,0) \( \huge c= \sqrt{36-4} \) Can you tell us what c equals?

  5. anonymous
    • one year ago
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    If you are wondering where I got 36, I got it from starting at (0,0) and counting to my right to the end where the circle meets the x axis, which is 6. Then I \( 6^2 = 36 \)

  6. anonymous
    • one year ago
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    You do the same for the y too

  7. anonymous
    • one year ago
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    What does c = ??

  8. anonymous
    • one year ago
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    4 sqrt 2?

  9. anonymous
    • one year ago
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    Yes correct!!! so your foci are at |dw:1438686871701:dw|

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