anonymous
  • anonymous
Graphing Radical Functions (just find domain and range.) Hi! I am working on the study of graphing radical functions. I have already graphed these functions, I just do not understand how to write domain&range for both. I have to write it in terms of "all real numbers" I will include all 5 graphs below. Would really appreciate help.
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Graph 1
1 Attachment
anonymous
  • anonymous
Graph 2
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anonymous
  • anonymous
Graph 3
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anonymous
  • anonymous
Graph 4
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anonymous
  • anonymous
Graph 5
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anonymous
  • anonymous
okay well basically you have to find the asymptote of each function and state that that's the only point that the function does not equal (e.g. all real numbers except"whatever x-intercept the asymptote is at")
anonymous
  • anonymous
do you know how to find the vertical asymptotes ?
anonymous
  • anonymous
I am not sure how to do that. I was sadly not introduced throughly to the unit :(
anonymous
  • anonymous
http://www.purplemath.com/modules/asymtote.htm
anonymous
  • anonymous
@Hero @pooja195 @triciaal
anonymous
  • anonymous
Yeah I am not totally understanding how to relate that to finding domain and range i'm a bit confused
Loser66
  • Loser66
For the first one, \(f(x) = \dfrac{1}{x+1}\) take denominator =0, solve for x, what do you get?
Loser66
  • Loser66
knock knock!!! x +1 =0, x =??
anonymous
  • anonymous
ok! one moment
anonymous
  • anonymous
-1 ?
Loser66
  • Loser66
yes, domain relate to x, right? but you can't take x =-1 since it makes the function undefined, right? Hence D = \(\mathbb R/{-1}\)
anonymous
  • anonymous
So that would make the domain for the first graph undefined then?
Loser66
  • Loser66
How about the range? Look at the graph, y goes from -infinitive to +infinitive but at 0, Hence Range is \(\mathbb R/0\)
Loser66
  • Loser66
A little bit difference. domain is all numbers of x that make the function defined. -1 makes the function undefined, hence domain is all real number BUT -1
anonymous
  • anonymous
ahhhhhhhhhhhhh. That makes sense. I understand. I never understood the "all real numbers except.. ext."
anonymous
  • anonymous
i'm sorry, I do not understand the notation- by "R/0" you mean that the range is all real numbers but 0?
anonymous
  • anonymous
I only ask because I have to format it in sentence form
Loser66
  • Loser66
yup
Loser66
  • Loser66
it is not R/0. It is \(\mathbb R/\{0\}\). That the correct notation.
anonymous
  • anonymous
Yes. My computer would not let me copy that. That is what I meant
anonymous
  • anonymous
Would you mind helping me with the others?
Loser66
  • Loser66
what is the second function? \(f(x) = \dfrac{1}{x-2}+1\)??
anonymous
  • anonymous
x would equal 2 here. would this mean that the domain is all real numbers except for 2?
Loser66
  • Loser66
yup
anonymous
  • anonymous
and how would I find the range? i did not totally understand how you did that for the first graph
Loser66
  • Loser66
to find the range of a radical function, you need asymptotes, that are the line the graph is never touch. like the graph of \(f(x) =\dfrac{1}{x-2}+1\) it looks like |dw:1438655236291:dw|
Loser66
  • Loser66
for domain, you see that x goes from -infinitive to + infinitive except x =2|dw:1438655384625:dw|
Loser66
  • Loser66
for range, look at y-axis.|dw:1438655427018:dw| the graph goes from -infinitive to +infinitive along y-axis but never have y =1, right? hence range is \(\mathbb R/\{1\}\)
anonymous
  • anonymous
ok. I understand

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