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anonymous
 one year ago
what values for theta(0≤theta≤2pi) satisfy the equation? 2sinthetacostheta+sqrt 3 theta
anonymous
 one year ago
what values for theta(0≤theta≤2pi) satisfy the equation? 2sinthetacostheta+sqrt 3 theta

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freckles
 one year ago
Best ResponseYou've already chosen the best response.3is there an equation?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3ok so you meant to put =0 at the end

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm really confused x.x why r practice packets so hard >:C

freckles
 one year ago
Best ResponseYou've already chosen the best response.3and the other cos thingy but yeah anyways you can factor the left hand side \[2 \sin(\theta)\cos(\theta)+\sqrt{3} \cos(\theta)=0 \\ \text{ factor out the } \cos(\theta) \\ \cos(\theta)[2 \sin(\theta)+\sqrt{3}]=0 \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3set both factors =0 and solve for theta

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[\cos(\theta) \text{ or } \sin(\theta) =\frac{\sqrt{3}}{2}\] use unit circle

freckles
 one year ago
Best ResponseYou've already chosen the best response.3forgot the =0 part :p

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[\cos(\theta)=0 \text{ or } \sin(\theta) =\frac{\sqrt{3}}{2}\] use unit circle *

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0??? wits the answer suppose to be :( explanation too pls

freckles
 one year ago
Best ResponseYou've already chosen the best response.3sin(theta) is the ycoordinate on the unit circle find for what theta's you have the y value ( the second value) of the pair is sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3hint: look in quadrants 3 and 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okie :( wait the answer is B??

freckles
 one year ago
Best ResponseYou've already chosen the best response.3sin(3pi/4) is not sqrt(3)/2 it is sqrt(2)/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so theres no answer? ._.

freckles
 one year ago
Best ResponseYou've already chosen the best response.3i didn't say that i just said the option you chose is incorrect because sin(3pi/4) is not sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3did you look at the unit circle you are looking for when the ycoordinate is sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3the hint I gave is to look in the 3rd and 4th quadrant

freckles
 one year ago
Best ResponseYou've already chosen the best response.3https://www.mathsisfun.com/geometry/images/circleunitradians.gif look at this picture do you see the ordered pairs?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3look at the second number of each pair you are looking to for which theta you have the y coordinate is sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3can you tell me looking at that chart thing where you see y coordinate is sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3ok look at that chart do you see under sin sqrt(3)/2 ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3find it then use your finger and move it horizontally from that number to the theta number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH I GET WUT MEAN ITS A DUH ITS 4PI/3 IM SO STUPID

freckles
 one year ago
Best ResponseYou've already chosen the best response.3yes sin(4pi/3)=sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3and sin(5pi/3)=sqrt(3)/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.3and of course cos(theta)=0 is easy to solve and all of the choices included its answers which was pi/2 and 3pi/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:D thnx so much here a medal
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