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anonymous

  • one year ago

what values for theta(0≤theta≤2pi) satisfy the equation? 2sinthetacostheta+sqrt 3 theta

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  1. freckles
    • one year ago
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    is there an equation?

  2. anonymous
    • one year ago
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    yeah

  3. anonymous
    • one year ago
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  4. freckles
    • one year ago
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    ok so you meant to put =0 at the end

  5. anonymous
    • one year ago
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    yeah

  6. anonymous
    • one year ago
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    I'm really confused x.x why r practice packets so hard >:C

  7. freckles
    • one year ago
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    and the other cos thingy but yeah anyways you can factor the left hand side \[2 \sin(\theta)\cos(\theta)+\sqrt{3} \cos(\theta)=0 \\ \text{ factor out the } \cos(\theta) \\ \cos(\theta)[2 \sin(\theta)+\sqrt{3}]=0 \]

  8. freckles
    • one year ago
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    set both factors =0 and solve for theta

  9. freckles
    • one year ago
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    \[\cos(\theta) \text{ or } \sin(\theta) =\frac{-\sqrt{3}}{2}\] use unit circle

  10. anonymous
    • one year ago
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    ??!!

  11. freckles
    • one year ago
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    forgot the =0 part :p

  12. freckles
    • one year ago
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    \[\cos(\theta)=0 \text{ or } \sin(\theta) =\frac{-\sqrt{3}}{2}\] use unit circle *

  13. anonymous
    • one year ago
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    ??? wits the answer suppose to be :( explanation too pls

  14. freckles
    • one year ago
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    sin(theta) is the y-coordinate on the unit circle find for what theta's you have the y value ( the second value) of the pair is -sqrt(3)/2

  15. freckles
    • one year ago
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    hint: look in quadrants 3 and 4

  16. anonymous
    • one year ago
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    okie :( wait the answer is B??

  17. freckles
    • one year ago
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    sin(3pi/4) is not -sqrt(3)/2 it is sqrt(2)/2

  18. anonymous
    • one year ago
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    so theres no answer? ._.

  19. freckles
    • one year ago
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    i didn't say that i just said the option you chose is incorrect because sin(3pi/4) is not -sqrt(3)/2

  20. freckles
    • one year ago
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    did you look at the unit circle you are looking for when the y-coordinate is -sqrt(3)/2

  21. anonymous
    • one year ago
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    D

  22. freckles
    • one year ago
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    the hint I gave is to look in the 3rd and 4th quadrant

  23. anonymous
    • one year ago
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    d??

  24. freckles
    • one year ago
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    https://www.mathsisfun.com/geometry/images/circle-unit-radians.gif look at this picture do you see the ordered pairs?

  25. freckles
    • one year ago
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    look at the second number of each pair you are looking to for which theta you have the y coordinate is -sqrt(3)/2

  26. freckles
    • one year ago
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    can you tell me looking at that chart thing where you see y coordinate is -sqrt(3)/2

  27. freckles
    • one year ago
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    ok look at that chart do you see under sin -sqrt(3)/2 ?

  28. freckles
    • one year ago
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    find it then use your finger and move it horizontally from that number to the theta number

  29. anonymous
    • one year ago
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    OH I GET WUT MEAN ITS A DUH ITS 4PI/3 IM SO STUPID

  30. freckles
    • one year ago
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    yes sin(4pi/3)=-sqrt(3)/2

  31. freckles
    • one year ago
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    and sin(5pi/3)=-sqrt(3)/2

  32. freckles
    • one year ago
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    and of course cos(theta)=0 is easy to solve and all of the choices included its answers which was pi/2 and 3pi/2

  33. anonymous
    • one year ago
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    :D thnx so much here a medal

  34. freckles
    • one year ago
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    np

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