anonymous
  • anonymous
2. Given the function k(x) = x2, compare and contrast how the application of a constant, c, affects the graph. The application of the constant must be discussed in the following manners: • k(x + c) • k(x) + c • k(cx) • c • k(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
@nincompoop @triciaal
anonymous
  • anonymous
@triciaal please help with my problem im lost my lession did not cover this information
triciaal
  • triciaal
|dw:1438661874421:dw|

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triciaal
  • triciaal
|dw:1438662106671:dw|
anonymous
  • anonymous
ok one more question. how do you determine if the average rate of change is increasing or decreasing, from left to right on a parabola. my equation that i graphed was F(x)=(x-2)(x+2)
triciaal
  • triciaal
what would be fast is to pick a value for c and plug into the calculator to see the changes and then describe them
triciaal
  • triciaal
you can use https://www.desmos.com/calculator
anonymous
  • anonymous
wait how do i pug in k(x)=x^2 into each example
triciaal
  • triciaal
do you mean how to input the function?
anonymous
  • anonymous
i suppose, snce the original equation says: given the function k(x) = x2, compare and contrast how the application of a constant, c, affects the graph im assuming they want to imput the function into each example given in the original equations to determine how they would affect the graph im still a little confused :/
anonymous
  • anonymous
@Zale101
triciaal
  • triciaal
1 Attachment
Zale101
  • Zale101
Is the constant 2 ?
triciaal
  • triciaal
ok match the name on the left and the color with the color of the graph here c = 2 hope this solves your problem
triciaal
  • triciaal
@Zale101 in this example yes
Zale101
  • Zale101
I see what's going on.
triciaal
  • triciaal
the second question the zeros are 2 and -2
anonymous
  • anonymous
but how exactly do i plug k(x)=x^2 into each equation ??
triciaal
  • triciaal
x^2 is the parent function
triciaal
  • triciaal
k(x) is the same as f(x) same as y
anonymous
  • anonymous
sorry :/ what exactly is a parent function ?/ what is its purpose?
anonymous
  • anonymous
Ohhh gotcha so y=x^2??
triciaal
  • triciaal
|dw:1438663661160:dw|
anonymous
  • anonymous
so for instance what would happen with this equation k(x + c) would it be x^2(x+2) or what?? idk
Zale101
  • Zale101
k(x)=x^2 A function is a rule, what ever is the input is the input inside the function. The function says k of whatever is whatever squared k(x+c)=(x+c)^2
Zale101
  • Zale101
Example: \(\Large k(\star)=\star^2\)
triciaal
  • triciaal
no instead of x it is now (x + c) in my example I used c= 2 so you could see what the effect is instead of x^2 it is now (x + 2)^2
triciaal
  • triciaal
y = x^2 is red parent function the original y = (x + 2)^2 is blue do you see that adding a positive value to the x component moves the graph c units to the left in this case 2 because c = 2
anonymous
  • anonymous
ok i think i somewhat understand now my last question Using your graph from question 4, describe if the average rate of change is increasing or decreasing, from left to right. Justify your observations by comparing the slopes calculated between at least three different pairs of points. the equation i graphed was f(x)=(x-2)(x+2)
anonymous
  • anonymous
@Jhannybean
triciaal
  • triciaal
|dw:1438664828955:dw|
triciaal
  • triciaal
ok bye
anonymous
  • anonymous
@UnkleRhaukus
anonymous
  • anonymous
@dan815
anonymous
  • anonymous
@Hero

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