anonymous
  • anonymous
Which of the following is false for
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
A. The y-axis is not an asymptote of f(x). B. The x-axis is an asymptote of f(x). C. x = –1 is not an asymptote of f(x). D. x = 1 is an asymptote of f(x)
anonymous
  • anonymous
@dan815 @pooja195 @jim_thompson5910

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
what do you have so far?
anonymous
  • anonymous
is it D?
jim_thompson5910
  • jim_thompson5910
why do you think it's D?
anonymous
  • anonymous
\[limf(x){x \rightarrow \infty}=0\] \[f'(x) = −\frac{10\,{x}^{5}−15\,{x}^{4}−20\,{x}^{3}+10\,x−5}{{x}^{8}−2\,{x}^{4}+1}\] \[lim f'(x){x \rightarrow \infty}=0\] so, f(x), x infinite is decreasing (f'(x) negative arround infinite) B.
anonymous
  • anonymous
okay i read y = 1 for some reason, iv graphed it and the table says x=1,0, and -1 are DNE
anonymous
  • anonymous
is it C then
jim_thompson5910
  • jim_thompson5910
yeah because x = -1 is an asymptote saying `x = –1 is not an asymptote of f(x).` is false
anonymous
  • anonymous
thank you very mucuh.

Looking for something else?

Not the answer you are looking for? Search for more explanations.