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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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  2. freckles
    • one year ago
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    multiplying a 3 by 2 with a 2 by 3 will result in a 3 by 3 the inner numbers have to match then the dimensions of the product will be the exterior numbers there

  3. anonymous
    • one year ago
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    wait, what do you mean 3 by 2 and 2 by 3?

  4. freckles
    • one year ago
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    those are the dimensions of your matrices respectively

  5. freckles
    • one year ago
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    anyways to find the entries you do rows from the first matrix with columns of the second matrix

  6. freckles
    • one year ago
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    for example entry 1 will be 2(5)+0(0)

  7. freckles
    • one year ago
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    in general the first element in the product matrix would look like this \[\left[\begin{matrix}a_{11} & a_{12} \\ a_{21} & a_{22} \\ a_{31} & a_{32}\end{matrix}\right] \cdot \left[\begin{matrix}b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23}\end{matrix}\right] \\ =\left[\begin{matrix}a_{11} \cdot b_{11}+a_{12} \cdot b_{21} & ? & ? \\ ? & ? & ? \\ ? & ? & ?\end{matrix}\right]\]

  8. freckles
    • one year ago
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    basically we did the dot product of <a11,a12> and <b11,b21>

  9. freckles
    • one year ago
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    to find the first entry that is

  10. freckles
    • one year ago
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    |dw:1438660253075:dw|

  11. anonymous
    • one year ago
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    this is so confusing, omg.

  12. dan815
    • one year ago
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    lol

  13. dan815
    • one year ago
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    do u want a formula?

  14. freckles
    • one year ago
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    |dw:1438660316576:dw|

  15. anonymous
    • one year ago
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    Oh, okay okay, I get it now! Thank you!

  16. freckles
    • one year ago
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    https://en.wikipedia.org/wiki/Matrix_multiplication just in case I don't really want to type it all out but wikepedia already did you can see they multiplied a 3 by 2 with a 2 by 3 here look under rectanglular matrices BA

  17. Jhannybean
    • one year ago
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    Whats the formula @dan815 :)

  18. freckles
    • one year ago
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    already did a formula for a 3 by 2 with a 2 by 3 *

  19. dan815
    • one year ago
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    |dw:1438660749700:dw|

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