6.) Find the surface area of the regular pyramid shown to the nearest whole number. The figure is not drawn to scale. http://assets.openstudy.com/updates/attachments/55bff878e4b03325500374c7-lollygirl217-1438647128464-as.jpg
my answer: 1,125 m^2. is that correct?
7.) What is the surface area of a conical grain storage tank that has a height of 37 meters and a diameter of 16 metes? Round the answer to the nearest square meter.
my answer: 1152 square meters.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

- schrodinger

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

is that correct?

- anonymous

- anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

- anonymous

- anonymous

@midhun.madhu1987

- anonymous

- anonymous

- anonymous

- anonymous

- anonymous

@Zale101 is it right? is it WRONG??

- anonymous

- anonymous

- anonymous

@.Sam.

- UnkleRhaukus

What did you get for the base of the pyramid?,
and what did you get for the area of each of the triangular faces?

- anonymous

hold on.

- anonymous

gane just messaged me saying i was right. 6) The area of the base is 6*(15 m)*(7.5âˆš3 m) = 675âˆš3 m^2 â‰ˆ 1169 m^2
.. The lateral area is 3*(15 m)*(12 m) = 540 m^2
.. The total area of base and sides is 1709 m^2.
7) The area of the base is Ï€*(8 m)^2 = 64Ï€ m^2 â‰ˆ 201 m^2
.. The lateral area is Ï€(8 m)*âˆš(37^2 + 8^2) m = 951 m^2
.. The total area of base and side surface is 1152 m^2.

- anonymous

oh...well the first one was not one of my options so I just went with the answer closest to it.

- UnkleRhaukus

you have the lateral surface area correct

- UnkleRhaukus

but what formula are you using to calculate the area of the hexagonal base?

- UnkleRhaukus

|dw:1438664885301:dw|

- UnkleRhaukus

don't forget the area of a triangle is bh/2

- UnkleRhaukus

(you forgot to divide by 2)

- anonymous

so 647m^2?

- anonymous

er hold on

- anonymous

540 m^2

- anonymous

Area of whole thing\[A=\frac{ 3\sqrt{3} }{ 2 }a^2\]
then divide by 6...

- UnkleRhaukus

The surface area of the pyramid is the sum of the area of its base, plus its lateral surface area
The base can be decomposed into six triangles
Area of base = 6 * (15m) * (7.5âˆš3m) /2
= 1169/2 m^2
= .... m^2
Lateral area = 3*(15 m)*(12 m) = 540 m^2
The total surface area
Area of base + Lateral area
= .... m^2 + 540 m^2
= ( ) m^2

- anonymous

just to confirm YOU ARE telling me that I am correct on number 7 but not 6? I could have gotten mixed up

- UnkleRhaukus

i never crunched the numbers,

- anonymous

...guys I am not fishing for answers I just want you to tell me if I am right or not.

- anonymous

Yes. No. That is all.

- UnkleRhaukus

OpenStudy isn't like that.

- Jhannybean

Thank you.

- anonymous

Actually it is, I have been getting corrected of my work since I got here. I havent come across this problem before until now. I don't know what you guys are talking about.

- anonymous

i dont have a calculator with me now but i can see the answer is >1000

- anonymous

It isn't cheating when you are just simply asking someone if you did something correctly. Pretty much all of you guys with 99 points have been coming in and correcting me no problem. @UnkleRhaukus and @Jhannybean are the only ones who are treating it differently.

- anonymous

Nevertheless, I will still award unkle.

- Jhannybean

Because we are not solving your problem on our own and telling you whether you are right or wrong is wasting your time? Crunch the numbers yourself with the guidance we gave you and you yourself will see whether it's right or wrong. It's not difficult at all.

- anonymous

But I am only looking for a simple yes or no. You two are overthinking this.

- anonymous

I havent had any problems with any other users

- anonymous

- UnkleRhaukus

i want you to learn geometry

- anonymous

The thing is, is that I already know it, i already solved the problem but I just want to KNOW IF I did it correctly.

- Jhannybean

Then you've got to show us your work.

- anonymous

I already did...lol

- UnkleRhaukus

you forgot to divide by two, like i said before

- anonymous

You said one before.

- anonymous

Anyways, gane already said i did them right.

- UnkleRhaukus

gane could be wrong

- anonymous

I'm sorry but he has corrected my work before and he was right every time.....because he is an honorary professor.

Looking for something else?

Not the answer you are looking for? Search for more explanations.