anonymous
  • anonymous
6.) Find the surface area of the regular pyramid shown to the nearest whole number. The figure is not drawn to scale. http://assets.openstudy.com/updates/attachments/55bff878e4b03325500374c7-lollygirl217-1438647128464-as.jpg my answer: 1,125 m^2. is that correct? 7.) What is the surface area of a conical grain storage tank that has a height of 37 meters and a diameter of 16 metes? Round the answer to the nearest square meter. my answer: 1152 square meters.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
is that correct?
anonymous
  • anonymous
@Abhisar
anonymous
  • anonymous
@triciaal

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More answers

anonymous
  • anonymous
@nincompoop
anonymous
  • anonymous
@Zale101
anonymous
  • anonymous
@midhun.madhu1987
anonymous
  • anonymous
@sleepyjess
anonymous
  • anonymous
@Miracrown @ganeshie8
anonymous
  • anonymous
@taramgrant0543664 @Jaynator495
anonymous
  • anonymous
@sugarplum15
anonymous
  • anonymous
@Zale101 is it right? is it WRONG??
anonymous
  • anonymous
@ganeshie8 @Abhisar
anonymous
  • anonymous
@UnkleRhaukus
anonymous
  • anonymous
@.Sam.
UnkleRhaukus
  • UnkleRhaukus
What did you get for the base of the pyramid?, and what did you get for the area of each of the triangular faces?
anonymous
  • anonymous
hold on.
anonymous
  • anonymous
gane just messaged me saying i was right. 6) The area of the base is 6*(15 m)*(7.5√3 m) = 675√3 m^2 ≈ 1169 m^2 .. The lateral area is 3*(15 m)*(12 m) = 540 m^2 .. The total area of base and sides is 1709 m^2. 7) The area of the base is π*(8 m)^2 = 64π m^2 ≈ 201 m^2 .. The lateral area is π(8 m)*√(37^2 + 8^2) m = 951 m^2 .. The total area of base and side surface is 1152 m^2.
anonymous
  • anonymous
oh...well the first one was not one of my options so I just went with the answer closest to it.
UnkleRhaukus
  • UnkleRhaukus
you have the lateral surface area correct
UnkleRhaukus
  • UnkleRhaukus
but what formula are you using to calculate the area of the hexagonal base?
UnkleRhaukus
  • UnkleRhaukus
|dw:1438664885301:dw|
UnkleRhaukus
  • UnkleRhaukus
don't forget the area of a triangle is bh/2
UnkleRhaukus
  • UnkleRhaukus
(you forgot to divide by 2)
anonymous
  • anonymous
so 647m^2?
anonymous
  • anonymous
er hold on
anonymous
  • anonymous
540 m^2
anonymous
  • anonymous
Area of whole thing\[A=\frac{ 3\sqrt{3} }{ 2 }a^2\] then divide by 6...
UnkleRhaukus
  • UnkleRhaukus
The surface area of the pyramid is the sum of the area of its base, plus its lateral surface area The base can be decomposed into six triangles Area of base = 6 * (15m) * (7.5√3m) /2 = 1169/2 m^2 = .... m^2 Lateral area = 3*(15 m)*(12 m) = 540 m^2 The total surface area Area of base + Lateral area = .... m^2 + 540 m^2 = ( ) m^2
anonymous
  • anonymous
just to confirm YOU ARE telling me that I am correct on number 7 but not 6? I could have gotten mixed up
UnkleRhaukus
  • UnkleRhaukus
i never crunched the numbers,
anonymous
  • anonymous
...guys I am not fishing for answers I just want you to tell me if I am right or not.
anonymous
  • anonymous
Yes. No. That is all.
UnkleRhaukus
  • UnkleRhaukus
OpenStudy isn't like that.
Jhannybean
  • Jhannybean
Thank you.
anonymous
  • anonymous
Actually it is, I have been getting corrected of my work since I got here. I havent come across this problem before until now. I don't know what you guys are talking about.
anonymous
  • anonymous
i dont have a calculator with me now but i can see the answer is >1000
anonymous
  • anonymous
It isn't cheating when you are just simply asking someone if you did something correctly. Pretty much all of you guys with 99 points have been coming in and correcting me no problem. @UnkleRhaukus and @Jhannybean are the only ones who are treating it differently.
anonymous
  • anonymous
Nevertheless, I will still award unkle.
Jhannybean
  • Jhannybean
Because we are not solving your problem on our own and telling you whether you are right or wrong is wasting your time? Crunch the numbers yourself with the guidance we gave you and you yourself will see whether it's right or wrong. It's not difficult at all.
anonymous
  • anonymous
But I am only looking for a simple yes or no. You two are overthinking this.
anonymous
  • anonymous
I havent had any problems with any other users
anonymous
  • anonymous
@Jhannybean
UnkleRhaukus
  • UnkleRhaukus
i want you to learn geometry
anonymous
  • anonymous
The thing is, is that I already know it, i already solved the problem but I just want to KNOW IF I did it correctly.
Jhannybean
  • Jhannybean
Then you've got to show us your work.
anonymous
  • anonymous
I already did...lol
UnkleRhaukus
  • UnkleRhaukus
you forgot to divide by two, like i said before
anonymous
  • anonymous
You said one before.
anonymous
  • anonymous
Anyways, gane already said i did them right.
UnkleRhaukus
  • UnkleRhaukus
gane could be wrong
anonymous
  • anonymous
I'm sorry but he has corrected my work before and he was right every time.....because he is an honorary professor.

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