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anonymous

  • one year ago

6.) Find the surface area of the regular pyramid shown to the nearest whole number. The figure is not drawn to scale. http://assets.openstudy.com/updates/attachments/55bff878e4b03325500374c7-lollygirl217-1438647128464-as.jpg my answer: 1,125 m^2. is that correct? 7.) What is the surface area of a conical grain storage tank that has a height of 37 meters and a diameter of 16 metes? Round the answer to the nearest square meter. my answer: 1152 square meters.

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  1. anonymous
    • one year ago
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    is that correct?

  2. anonymous
    • one year ago
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    @Abhisar

  3. anonymous
    • one year ago
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    @triciaal

  4. anonymous
    • one year ago
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    @nincompoop

  5. anonymous
    • one year ago
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    @Zale101

  6. anonymous
    • one year ago
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    @midhun.madhu1987

  7. anonymous
    • one year ago
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    @sleepyjess

  8. anonymous
    • one year ago
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    @Miracrown @ganeshie8

  9. anonymous
    • one year ago
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    @taramgrant0543664 @Jaynator495

  10. anonymous
    • one year ago
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    @sugarplum15

  11. anonymous
    • one year ago
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    @Zale101 is it right? is it WRONG??

  12. anonymous
    • one year ago
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    @ganeshie8 @Abhisar

  13. anonymous
    • one year ago
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    @UnkleRhaukus

  14. anonymous
    • one year ago
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    @.Sam.

  15. UnkleRhaukus
    • one year ago
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    What did you get for the base of the pyramid?, and what did you get for the area of each of the triangular faces?

  16. anonymous
    • one year ago
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    hold on.

  17. anonymous
    • one year ago
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    gane just messaged me saying i was right. 6) The area of the base is 6*(15 m)*(7.5√3 m) = 675√3 m^2 ≈ 1169 m^2 .. The lateral area is 3*(15 m)*(12 m) = 540 m^2 .. The total area of base and sides is 1709 m^2. 7) The area of the base is π*(8 m)^2 = 64π m^2 ≈ 201 m^2 .. The lateral area is π(8 m)*√(37^2 + 8^2) m = 951 m^2 .. The total area of base and side surface is 1152 m^2.

  18. anonymous
    • one year ago
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    oh...well the first one was not one of my options so I just went with the answer closest to it.

  19. UnkleRhaukus
    • one year ago
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    you have the lateral surface area correct

  20. UnkleRhaukus
    • one year ago
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    but what formula are you using to calculate the area of the hexagonal base?

  21. UnkleRhaukus
    • one year ago
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    |dw:1438664885301:dw|

  22. UnkleRhaukus
    • one year ago
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    don't forget the area of a triangle is bh/2

  23. UnkleRhaukus
    • one year ago
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    (you forgot to divide by 2)

  24. anonymous
    • one year ago
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    so 647m^2?

  25. anonymous
    • one year ago
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    er hold on

  26. anonymous
    • one year ago
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    540 m^2

  27. anonymous
    • one year ago
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    Area of whole thing\[A=\frac{ 3\sqrt{3} }{ 2 }a^2\] then divide by 6...

  28. UnkleRhaukus
    • one year ago
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    The surface area of the pyramid is the sum of the area of its base, plus its lateral surface area The base can be decomposed into six triangles Area of base = 6 * (15m) * (7.5√3m) /2 = 1169/2 m^2 = .... m^2 Lateral area = 3*(15 m)*(12 m) = 540 m^2 The total surface area Area of base + Lateral area = .... m^2 + 540 m^2 = ( ) m^2

  29. Jhannybean
    • one year ago
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    http://openstudy.com/study#/updates/55c038dae4b0332550038575

  30. anonymous
    • one year ago
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    just to confirm YOU ARE telling me that I am correct on number 7 but not 6? I could have gotten mixed up

  31. UnkleRhaukus
    • one year ago
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    i never crunched the numbers,

  32. anonymous
    • one year ago
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    ...guys I am not fishing for answers I just want you to tell me if I am right or not.

  33. anonymous
    • one year ago
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    Yes. No. That is all.

  34. UnkleRhaukus
    • one year ago
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    OpenStudy isn't like that.

  35. Jhannybean
    • one year ago
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    Thank you.

  36. anonymous
    • one year ago
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    Actually it is, I have been getting corrected of my work since I got here. I havent come across this problem before until now. I don't know what you guys are talking about.

  37. anonymous
    • one year ago
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    i dont have a calculator with me now but i can see the answer is >1000

  38. anonymous
    • one year ago
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    It isn't cheating when you are just simply asking someone if you did something correctly. Pretty much all of you guys with 99 points have been coming in and correcting me no problem. @UnkleRhaukus and @Jhannybean are the only ones who are treating it differently.

  39. anonymous
    • one year ago
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    Nevertheless, I will still award unkle.

  40. Jhannybean
    • one year ago
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    Because we are not solving your problem on our own and telling you whether you are right or wrong is wasting your time? Crunch the numbers yourself with the guidance we gave you and you yourself will see whether it's right or wrong. It's not difficult at all.

  41. anonymous
    • one year ago
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    But I am only looking for a simple yes or no. You two are overthinking this.

  42. anonymous
    • one year ago
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    I havent had any problems with any other users

  43. anonymous
    • one year ago
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    @Jhannybean

  44. UnkleRhaukus
    • one year ago
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    i want you to learn geometry

  45. anonymous
    • one year ago
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    The thing is, is that I already know it, i already solved the problem but I just want to KNOW IF I did it correctly.

  46. Jhannybean
    • one year ago
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    Then you've got to show us your work.

  47. anonymous
    • one year ago
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    I already did...lol

  48. UnkleRhaukus
    • one year ago
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    you forgot to divide by two, like i said before

  49. anonymous
    • one year ago
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    You said one before.

  50. anonymous
    • one year ago
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    Anyways, gane already said i did them right.

  51. UnkleRhaukus
    • one year ago
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    gane could be wrong

  52. anonymous
    • one year ago
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    I'm sorry but he has corrected my work before and he was right every time.....because he is an honorary professor.

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