Write the quadratic function in vertex form. y = x2 + 8x + 18

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Write the quadratic function in vertex form. y = x2 + 8x + 18

Mathematics
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i know you have to Subtract 18 from both sides: y - 18 = x^2 + 8x Complete the square by adding 16 to both sides: y - 18 + 16 = x^2 + 8x + 16 y - 2 = x^2 + 8x + 16 Express x^2 + 8x + 16 in binomial square form: y - 2 = (x + 4)^2 Add 2 to both sides: y = (x + 4)^2 + 2
You can use the vertex formula to figure out the max height: t=−b2a t=−6402(−16) t=20 Next you'll need to insert t = 20 into the given equation: h(20) = - 16(20)^2 + 640(20)
then simplify the expression on the right to solve for h(20)

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Other answers:

how would you solve for h(20)
h(20) = - 16(20)^2 + 640(20)
how did it turn from t into h?
i have no idea im using this
ok the general form of a parabola looks like this \[x^2=4py\] and the standard forms are the messy quadratic equations
like that graph right?
\[x^2+8x+18=0\]since you cant factorize this you need to complete the square\[x^2+8x=-18\]\[x^2+8x+(\frac{ 8 }{ 2 })^2=-18+(\frac{ 8 }{ 2 })^2\]\[x^2+8x+16=-18+16\]\[(x+4)^2=-2\]
dont worry about that graph thing yet
ok
thank you
you can understand it so far?
kinda
lol
that means you dont understand...
would it be - instead of the +
\[(x+4)^2=-2\]\[(x+4)^2+2=0\]
ugh yes!

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