y = 8x − 9 y = 4x − 1 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer.

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y = 8x − 9 y = 4x − 1 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer.

Mathematics
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what is a variable that u can eliminate?
X? I think. I'm completely lost
treat this as an equation

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Other answers:

You can add or subtract to eliminate a letter (x or y).
\[\frac{ y=8x-9 } { y=4x-1 }\]
so can you see any thing that can be eliminated by subtraction or addition?
hello??
9-1??? Sorry I didn't reply I got sidetracked
do u know wit a variable is?
I'm sorry I really need help I suck at math pls
For part B, we graph these two equations y=8x-9 and y= 4x-1 then the point of intersection is when there is a solution for both of these equations
For part A. substitution is a better choice.
u can eliminate y
so it becomes \[\frac{ 8x-9 }{ 4x-1 }\]
Why would you say that I came on here for help because I care about my education not to be insulted by rude people like you.
and how the heck can you solve with that?
anyway set these two equations together 8x-9 = 4x-1 put all variables to the left and all numbers to the right 8x-4x=-1+9 now what's 8x-4x and what's -1+9 ?
Fine I don't want your help. You didn't hack me shut up.
-_- ughhhh @ganeshie8
@Icedragon50 stop creating drama on here. Just leave if you can't help nicely to other OS users.
Thank you @usukidoll for actually helping me
\[8x-y=9\]\[4x-y=1\]
looking it this way might help
@saseal that works too elimination or substitution can give the same results.
-1+9=8 thanks so much
forgot one part though 8x-4x=-1+9 now what's 8x-4x and what's -1+9 ? what's 8x-4x ?
yea its easier to put in matrix form that way :)
true, but most of the time , matrix form versions are taught way later o_O.
@andrea0529 what's 8x-4x ? or an easier way to put it by factoring the x x(8-4) what's 8-4 ?
4x
yea, once you go matrix you dont go back!
:) so now we have 4x = 8 we divide 4 from both sides so what's 8/4 ?
8 divided by 4 @andrea0529 then we have x by itself after that step.
|dw:1438679720781:dw|
8/4=2 so x=2
yes so now that we have x = 2 , we can plug it into one of the equations to solve for y let's pick the second equation y=4x-1 so we plug in x = 2 into y = 4x-1 y=4(2)-1 y=8-1 = ? what's 8-1 ?
8-1=7
mhm so x = 2 and y = 7 we can plug these numbers back to the equation to see if they hold true. That means we have done this correctly
7=4(2)-1 7=8-1 7=7 7=8(2)-9 7=16-9 7=7
so we have done this correctly. Apparently at the point (2,7) the two lines should intersect
but it's asking for a graph so we need to make tables... -_- we can let x = 0,1,2 to solve for y for y = 8x-9 and y = 4x-1
|dw:1438680048402:dw| so for this chart we plug in x= 0 for those 2 equations... similarly plug in x = 1 for those two equations as well until we hit the x = 2 which results in 7 for both equations
|dw:1438680137485:dw| so can you plug x = 0 for y = 8x-9 y=4x-1 and can you plug x = 1 for y=8x-9 y=4x-1 ??? since x = 2 is done already, I've wrote y = 7 on both of them.
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yeah what this guy wrote ^
because graphing manually is a pain. I think I overshot part b. oh well .
but (2,7) is a point that two lines cross (point of intersection) and there is one solution when we have perpendicular lines.
@andrea0529 overshot part b. it was just asking the point of intersection with is (2,7) .
Okay I get it know I mostly needed help with part a. I've got part b. Thank you so much.☺️

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