## anonymous one year ago can you please check if i am correct?

1. anonymous

2. anonymous

3. anonymous

@Elsa213

4. mathmate

#1, 2 are correct. #3 hint: -x<4 is the same as x>-4 (i.e. the direction of inequality is reversed when you negate an inequality) #4 "or" means either one works, so the two part-answers are additive #5 is correct #6 work out the two cases 2x+4>14 and -2x-4>14 then take intersection of the two results, i.e. the part of the result that satisfies both cases. #7 draw on number line each option and figure out the right answer, which should be equivalent to -40<F<257 #8 is correct.

5. anonymous

thanks! @mathmate

6. mathmate

you're welcome! :)

7. anonymous

@mathmate for 3 it would be D right? and can you help me figure out 7 please?

8. anonymous

and let me rephrase that. for 3 it would be A right? @mathmate

9. mathmate

#3 3<x<6 is correct. Please state the values when checking the answer, instead of the letters. For #7, recognize that 5/9(F-32) is the same temperature in Celsius. Also, all options have two separate inequalities, so you need the equivalent of -40<F, or -40<C, for the lower limit, and F<257 or C<125 for the upper limit. So check out each option to see which one has both conditions.

10. anonymous

@mathmate 3<x<6 would be A am i correct?

11. mathmate

For #3, 3<x<6 would be correct. I will leave that to you to find the options! Remember that an empty dot refers to strict inequality, and a solid dot refers to >= or <=.

12. anonymous

@mathmate thanks

13. anonymous

@Michele_Laino

14. Michele_Laino

-40 F= -40 C furthermore: 125 °C= 257 °F I have used this formula: $F = \frac{9}{5}C + 32$

15. anonymous

@Michele_Laino can you help me figure the ones that are not correct out please?

16. Michele_Laino

it is simple, you have to compute how many Fahrenheit degrees are these temperatures -40 C and 125 C

17. anonymous

-40 C = -40 F 125 C = 257 F what would i do next ?

18. anonymous

@Michele_Laino i know its either A or B now

19. Michele_Laino

It is option B)

20. anonymous

thankss!! can you help me out with #3?

21. Michele_Laino

here we have to solve this inequality: $- 13 > - 5x + 2 > - 28$

22. Michele_Laino

actually, they are two inequalities

23. anonymous

what would they be? @Michele_Laino

24. Michele_Laino

the first inequality is: $- 13 > - 5x + 2$ whereas the second one is: $- 5x + 2 > - 28$ please solve them

25. anonymous

first: X>3 second: X<6 correct? @Michele_Laino

26. Michele_Laino

yes! correct!

27. anonymous

@Michele_Laino I'm thinking a what do you think?

28. anonymous

@Michele_Laino

29. anonymous

@mathstudent55

30. Michele_Laino

yes! correct!

31. anonymous

THANK YOUUU! look. i know I'm really annoying and everything but can you please help me with 4? @Michele_Laino

32. Michele_Laino

here, you have to solve these inequalities: $\Large \begin{gathered} 4p + 1 > - 7 \hfill \\ 6p + 3 < 33 \hfill \\ \end{gathered}$ what do you get?

33. anonymous

P>-2 P<5 @Michele_laino

34. Michele_Laino

so, what is the right option?

35. anonymous

@Michele_Laino i don't know. the person up there said it wasn't A so i don't know

36. Michele_Laino

I think it is A

37. anonymous

can you teach me find the 2 inequalities so that i can solve 6 please? @Michele_Laino

38. Michele_Laino

the proposed inequlity is equivalent to these two systems of inequalities: $\Large \left\{ \begin{gathered} 2x + 4 < 14 \hfill \\ 2x + 4 \geqslant 0 \hfill \\ \end{gathered} \right. \cup \left\{ {\begin{array}{*{20}{c}} { - 2x - 4 < 14} \\ {2x + 4 < 0} \end{array}} \right.$ please solve them

39. anonymous

for both them is (-2,5) (-9,2) @Michele_Laino right?

40. Michele_Laino

the first inequality gives x>-9 and the second one gives x<-2, so the intersection is: (-9,-2)

41. Michele_Laino

the first solution is correct!

42. Michele_Laino

more precisely the first solution, is: [-2,5)

43. anonymous

quick question though. theres a point on a -5 on the number line and you got a -2.... is it supposed to be like that? @Michele_Laino

44. Michele_Laino

I don't understand, please specify more

45. anonymous

never mind i am seeing double from not sleeping my bad sorry haha @Michele_Laino

46. Michele_Laino

ok! :)

47. anonymous

@t.ashleyxx

48. anonymous

@HelloKitty17

49. anonymous

What would seem to be the problem?

50. anonymous

let me update this. because i fixed some questions. @t.ashleyxx