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anonymous
 one year ago
PLEASE HELP! A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezingpoint depression of the solvent if the freezing point constant is 1.86 °C/m? Show all of the work needed to solve this problem.
anonymous
 one year ago
PLEASE HELP! A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezingpoint depression of the solvent if the freezing point constant is 1.86 °C/m? Show all of the work needed to solve this problem.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sweetburger @peachpi @mathway

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0so you need to find the molality which from what i remember is moles of solute/ kg of solvent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sweetburger I got 735.33

cuanchi
 one year ago
Best ResponseYou've already chosen the best response.1"m" it is not mass, it is represent molality or moles of solute per kg of solvent, you have to calculate the molality of the solution to calculate the delta T. The delta T is the difference between the freezing point of the pure solvent and the freezing point of the solution. Then the T freezing point of the pure solvent in this case water I think you may know the value or you can find it in the internet. knowing that and the delta T you can calculate the freezing point of the solution.
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