A line passes through point (3, 7) and has a slope of 3/4
Stacey Warren - Expert brainly.com
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Let the required line be y = mx+c in the slope intercept form, where m is the slope and c is the y intercept.
We determine m and c by the using given conditions.
m = 3/4, given.
So y = (3/4)x+c (1).
The line at (1) has the point (-8, 4) on it.
Therefore 4 = (3/4)*(-8)+c...(2)
(1)-(2) gives: y-4 = (3/4)(x+8).
=> y -4 = (3/4)x + 6
We multiply 4 to get integral coefficients.
4(y-4) = 3x+24
3x-4y+40 = 0 is the required line.
the options are- y=3/4x+19/4 and y=3x-19
what do you think it would be the answer?
but im not sure
An easier approach for me atlest is this way:
(3, 7) and has a slope of 3/4
from here after you distribute and solve for y you get
So what you said is correct
If point A(x, 5) lies on the line, the value of x is 33 or 1/3