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anonymous

  • one year ago

FAN AND MEDAL**PLEASE HELP ME ITS MY LAST QUESTION, (i dont understand the fk qs) :(

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  1. anonymous
    • one year ago
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    Now that the curve pieces are determined, use those pieces as sections of a complete coaster. By hand or by using a drawing program, sketch a design of Ray and Kelsey's coaster that includes the shape of the g(x) and f(x) functions that you chose in the Parts A and B. You do not have to include the coordinate plane. You may arrange the functions in any order you choose, but label each section of the graph with the corresponding function for your instructor to view.

  2. anonymous
    • one year ago
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    @igreen @Peaches15 @ganeshie8

  3. anonymous
    • one year ago
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    @EmilyF03 This will help: http://www.peeranswer.com/study/mathematics/55b2d331b0447d5d5d4ddbea

  4. anonymous
    • one year ago
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    Here @EmilyF03 https://answers.yahoo.com/question/index?qid=20150725104721AAViLwr

  5. anonymous
    • one year ago
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    @Michele_Laino @johnweldon1993

  6. anonymous
    • one year ago
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    uuugghhh you stole my answer i was going to do that

  7. anonymous
    • one year ago
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    im not sure

  8. anonymous
    • one year ago
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    @pooja195

  9. Michele_Laino
    • one year ago
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    I need to know the equations of the function f(x) and g(x)

  10. anonymous
    • one year ago
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    okay wait

  11. anonymous
    • one year ago
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    f(x) = ax2 + bx + c. g(x) = x3 − x2 − 4x + 4

  12. anonymous
    • one year ago
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    @Michele_Laino help plz

  13. Michele_Laino
    • one year ago
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    do you know the values of the coefficients a, b, and c, of f(x) function?

  14. anonymous
    • one year ago
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    no ;/

  15. anonymous
    • one year ago
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    @Michele_Laino

  16. anonymous
    • one year ago
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    (a, 0), (b, 0), and (c, 0)?

  17. anonymous
    • one year ago
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    that doesnt help

  18. anonymous
    • one year ago
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    i can sort of visualize it as something like this |dw:1438704358155:dw|

  19. anonymous
    • one year ago
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    oh let me see

  20. anonymous
    • one year ago
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    no i dont know

  21. anonymous
    • one year ago
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    ;/

  22. anonymous
    • one year ago
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    |dw:1438704520152:dw|

  23. anonymous
    • one year ago
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    takes how g(x) looks like

  24. anonymous
    • one year ago
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    that's*

  25. anonymous
    • one year ago
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    i have the same graph, i remenber now

  26. anonymous
    • one year ago
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    you might have to look at your previous questions

  27. Michele_Laino
    • one year ago
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    if we don't know the coefficients a, b and c of f(x), I'm not able to draw the graph of f(x)

  28. anonymous
    • one year ago
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    agreed. because the parabola can fly anywhere.

  29. anonymous
    • one year ago
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    |dw:1438704917717:dw|

  30. anonymous
    • one year ago
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    you have this value?|dw:1438705039732:dw|

  31. anonymous
    • one year ago
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    x=0?

  32. anonymous
    • one year ago
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    no the x intercept

  33. anonymous
    • one year ago
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    x=2

  34. anonymous
    • one year ago
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    x - intercepts 2, -2, 1

  35. anonymous
    • one year ago
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    no not the g(x) curve. the f(x)

  36. anonymous
    • one year ago
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    because ax^2+bx+c cant be a straight line unless your a is 0

  37. anonymous
    • one year ago
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    g(x) looks like this

  38. anonymous
    • one year ago
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    oh

  39. anonymous
    • one year ago
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    |dw:1438705644333:dw|

  40. anonymous
    • one year ago
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    now you need to plot f(x) but i cant help you with it unless i have the coefficients of the function

  41. anonymous
    • one year ago
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    yes plz

  42. anonymous
    • one year ago
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    telling me f(x)=ax^2+bx+c doesnt help :(

  43. anonymous
    • one year ago
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    a=0 b=0 c=0

  44. anonymous
    • one year ago
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    then theres nothing to plot for f(x) its 0 anyway

  45. anonymous
    • one year ago
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    so... what i need to do now?

  46. anonymous
    • one year ago
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    we are done

  47. anonymous
    • one year ago
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    really? so the answers its a=0 b=0 c=0?

  48. anonymous
    • one year ago
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    it seems that you dont understand the question

  49. anonymous
    • one year ago
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    and if thats the answer you give...we arent done yet.

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