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anonymous

  • one year ago

In a closed flask, sulfur dioxide and oxygen react to produce sulfur trioxide. 2SO2(g) + O2(g) Double arrow yields 2SO3(g) In a graph of reaction rate versus time, what is occurring in this closed system when the curve for the rate of the SO2(g) reaction is horizontal? The concentration of SO2(g) is decreasing as the reaction continues. The concentrations of SO2(g) and SO3(g) are equal. The rate that SO2(g) reacts equals the rate that SO3(g) decomposes. The SO2(g) has been consumed until there is no more in the flask.

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  1. anonymous
    • one year ago
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    @JFraser a?

  2. JFraser
    • one year ago
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    when the concentration of \(SO_2\) graph is horizontal vs. time, is the concentration changing?

  3. anonymous
    • one year ago
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    yea so c is correct?

  4. JFraser
    • one year ago
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    it is

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