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anonymous

  • one year ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = -2x^4 + 4x^3 + 3x^2 + 18

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  1. anonymous
    • one year ago
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    Lol do you need help with this one ?

  2. anonymous
    • one year ago
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    please !!!!!!!!!

  3. anonymous
    • one year ago
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    what are the factors of the leading coefficient? what are the factors of the constant term?

  4. anonymous
    • one year ago
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    Similar problem as an example ; f(x) = -2x^3 + 3x^2 -2x +8 Solution: Factors of the constant term (8) / Factors of the leading coefficient (-2) so that would be: 1, 2, 4, 8 / 1, 2 So then each numerator over each denominator is a rational zero.... +/- 1/1, +/- 2/1, +/- 4/1, +/- 8/1, +/- 1/2, +/- 2/2, +/- 4/2, and +/- 8/2 Simplified: +/- 1, +/- 2, +/- 4, +/- 8, +/- 1/2, +/-1, +/- 2, and +/- 4 There are some duplicates so you can "drop" them... So your final answer is: +/- 1/2, +/- 1, +/- 2, +/- 4, +/- 8

  5. anonymous
    • one year ago
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    omg this is so confusing

  6. anonymous
    • one year ago
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    f(x) = -2x^4 + 4x^3 + 3x^2 + 18 constant term? Factors of the leading coefficient?

  7. anonymous
    • one year ago
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    http://softmath.com/tutorials-3/reducing-fractions/the-real-zeros-of-a-polynomial.html

  8. anonymous
    • one year ago
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    factors of 2: 1,2 factors of 18: 1,2,3,4,6,18 so some examples include 1/1,1/2,2/1,2/2,3/1,3/2,...

  9. anonymous
    • one year ago
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    ok

  10. anonymous
    • one year ago
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    so what are constant term? Factors of the leading coefficient? and do i need to do that for every number?

  11. anonymous
    • one year ago
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    @jenny1003

  12. anonymous
    • one year ago
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    -2 and 18 Sorry I'm helping alot of ppl at the same time

  13. anonymous
    • one year ago
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    factors of 2: 1,2 factors of 18: 1,2,3,4,6,18 factors of 4: 1,2,4 factors of 13: 1,3,

  14. anonymous
    • one year ago
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    3 not 13

  15. anonymous
    • one year ago
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    The leading term of a polynomial is the term of highest degree. The leading coefficient of a polynomial is the coefficient of the leading term. The degree of a polynomial is the degree of the leading term.

  16. anonymous
    • one year ago
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    leading term 4 leading coefficient -2

  17. anonymous
    • one year ago
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    I'm lost right now

  18. anonymous
    • one year ago
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    i am too

  19. anonymous
    • one year ago
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  20. anonymous
    • one year ago
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    @200205650 Please help....Srry

  21. anonymous
    • one year ago
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    http://www.mcg.net/nelson/CHAT/math/precalculus/overheads/sec.%202.5.pdf

  22. anonymous
    • one year ago
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    So you are pretty much solving for x in this equation right?

  23. anonymous
    • one year ago
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    i don't really know :O

  24. anonymous
    • one year ago
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    @ParthKohli

  25. anonymous
    • one year ago
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    http://www.virtualnerd.com/tutorials/?id=Alg2_06_01_0020

  26. anonymous
    • one year ago
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    This video might help in solving this problem. And yes you are trying to find what are all the numbers that can equal x. Factoring is one way of solving this problem. I can help you if you don't know how to factor this problem.

  27. anonymous
    • one year ago
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    @ganeshie8 @nincompoop

  28. anonymous
    • one year ago
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    @Peaches15

  29. anonymous
    • one year ago
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    @DanTheMan99

  30. anonymous
    • one year ago
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    i just saw the video, but still i can't understand

  31. anonymous
    • one year ago
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    Did you watch the whole thing?

  32. anonymous
    • one year ago
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    yes

  33. anonymous
    • one year ago
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    jk

  34. anonymous
    • one year ago
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    i didn't

  35. anonymous
    • one year ago
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    i saw the beginning

  36. anonymous
    • one year ago
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    Okay why don't you watch that video and I'll try to solve this problem using factoring. Is that fine?

  37. anonymous
    • one year ago
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    thank you

  38. anonymous
    • one year ago
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    No problem!

  39. anonymous
    • one year ago
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    @DanTheMan99 check this out http://www.wolframalpha.com/input/?i=f%28x%29+%3D+-2x%5E4+%2B+4x%5E3+%2B+3x%5E2+%2B+18

  40. anonymous
    • one year ago
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    \[-2x^4+4x^3+3x^2+18\]\[-2x^3(x-2)+3(x^2+6)\]\[(-2x^3+3)(x-2)(x^2+6)\] Equation #1:\[(-2x^3+3)=0\]\[-2x^3=-3\]\[x^3=\frac{ 3 }{ 2 }\]\[x=0.72112\] Equation#2: \[(x-2)=0\]\[x=2\] Equation #3:\[(x^2+6)=0\]\[x^2=-6\]\[x=\sqrt{6}i\]

  41. anonymous
    • one year ago
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    thank you guys so much

  42. anonymous
    • one year ago
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    You're welcome!

  43. anonymous
    • one year ago
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    Greatly done, @200205650

  44. anonymous
    • one year ago
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    Thanks!

  45. anonymous
    • one year ago
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    + 1/2, + 1, + 2, + 4, + 8, - 1/2, - 1, - 2, - 4, and -8.

  46. anonymous
    • one year ago
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  47. anonymous
    • one year ago
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    i don't know how to answer

  48. anonymous
    • one year ago
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    like how to put it into words

  49. anonymous
    • one year ago
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    ugh

  50. anonymous
    • one year ago
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    @nono266 please help me

  51. anonymous
    • one year ago
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  52. anonymous
    • one year ago
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    what should i write

  53. OregonDuck
    • one year ago
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    you have it written fine

  54. anonymous
    • one year ago
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    i know but whats my explanation

  55. anonymous
    • one year ago
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    like what proof can i give

  56. OregonDuck
    • one year ago
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    there is no need to do so

  57. anonymous
    • one year ago
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    are you sure

  58. OregonDuck
    • one year ago
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    100% positive

  59. OregonDuck
    • one year ago
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    is this flvs?

  60. anonymous
    • one year ago
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    yeah

  61. OregonDuck
    • one year ago
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    ok then yeah you do not need to

  62. OregonDuck
    • one year ago
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    for sure

  63. OregonDuck
    • one year ago
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    it is fine if you have the right answer then they know you understand it

  64. anonymous
    • one year ago
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    ok thanks

  65. OregonDuck
    • one year ago
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    do i get 10 owl bucks because i need them

  66. OregonDuck
    • one year ago
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    ?????????????

  67. OregonDuck
    • one year ago
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    do you have paypal?

  68. anonymous
    • one year ago
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    no

  69. OregonDuck
    • one year ago
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    can you ask the question for me and i go under it. ask a qualified helper question

  70. OregonDuck
    • one year ago
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    ask the question as ALGEBRA 1 HELP THEN I WILL ADD THE REST

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