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anonymous
 one year ago
Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.
f(x) = 2x^4 + 4x^3 + 3x^2 + 18
anonymous
 one year ago
Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = 2x^4 + 4x^3 + 3x^2 + 18

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol do you need help with this one ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what are the factors of the leading coefficient? what are the factors of the constant term?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Similar problem as an example ; f(x) = 2x^3 + 3x^2 2x +8 Solution: Factors of the constant term (8) / Factors of the leading coefficient (2) so that would be: 1, 2, 4, 8 / 1, 2 So then each numerator over each denominator is a rational zero.... +/ 1/1, +/ 2/1, +/ 4/1, +/ 8/1, +/ 1/2, +/ 2/2, +/ 4/2, and +/ 8/2 Simplified: +/ 1, +/ 2, +/ 4, +/ 8, +/ 1/2, +/1, +/ 2, and +/ 4 There are some duplicates so you can "drop" them... So your final answer is: +/ 1/2, +/ 1, +/ 2, +/ 4, +/ 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg this is so confusing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x) = 2x^4 + 4x^3 + 3x^2 + 18 constant term? Factors of the leading coefficient?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://softmath.com/tutorials3/reducingfractions/therealzerosofapolynomial.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factors of 2: 1,2 factors of 18: 1,2,3,4,6,18 so some examples include 1/1,1/2,2/1,2/2,3/1,3/2,...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what are constant term? Factors of the leading coefficient? and do i need to do that for every number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 and 18 Sorry I'm helping alot of ppl at the same time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factors of 2: 1,2 factors of 18: 1,2,3,4,6,18 factors of 4: 1,2,4 factors of 13: 1,3,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The leading term of a polynomial is the term of highest degree. The leading coefficient of a polynomial is the coefficient of the leading term. The degree of a polynomial is the degree of the leading term.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0leading term 4 leading coefficient 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@200205650 Please help....Srry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.mcg.net/nelson/CHAT/math/precalculus/overheads/sec.%202.5.pdf

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you are pretty much solving for x in this equation right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't really know :O

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This video might help in solving this problem. And yes you are trying to find what are all the numbers that can equal x. Factoring is one way of solving this problem. I can help you if you don't know how to factor this problem.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @nincompoop

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just saw the video, but still i can't understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Did you watch the whole thing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay why don't you watch that video and I'll try to solve this problem using factoring. Is that fine?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanTheMan99 check this out http://www.wolframalpha.com/input/?i=f%28x%29+%3D+2x%5E4+%2B+4x%5E3+%2B+3x%5E2+%2B+18

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2x^4+4x^3+3x^2+18\]\[2x^3(x2)+3(x^2+6)\]\[(2x^3+3)(x2)(x^2+6)\] Equation #1:\[(2x^3+3)=0\]\[2x^3=3\]\[x^3=\frac{ 3 }{ 2 }\]\[x=0.72112\] Equation#2: \[(x2)=0\]\[x=2\] Equation #3:\[(x^2+6)=0\]\[x^2=6\]\[x=\sqrt{6}i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you guys so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Greatly done, @200205650

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0+ 1/2, + 1, + 2, + 4, + 8,  1/2,  1,  2,  4, and 8.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't know how to answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like how to put it into words

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@nono266 please help me

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0you have it written fine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know but whats my explanation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like what proof can i give

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0there is no need to do so

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0ok then yeah you do not need to

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0it is fine if you have the right answer then they know you understand it

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0do i get 10 owl bucks because i need them

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0do you have paypal?

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0can you ask the question for me and i go under it. ask a qualified helper question

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0ask the question as ALGEBRA 1 HELP THEN I WILL ADD THE REST
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