Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.
f(x) = -2x^4 + 4x^3 + 3x^2 + 18

- anonymous

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- katieb

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- anonymous

Lol do you need help with this one ?

- anonymous

please
!!!!!!!!!

- anonymous

what are the factors of the leading coefficient? what are the factors of the constant term?

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## More answers

- anonymous

Similar problem as an example ;
f(x) = -2x^3 + 3x^2 -2x +8
Solution: Factors of the constant term (8) / Factors of the leading coefficient (-2)
so that would be: 1, 2, 4, 8 / 1, 2
So then each numerator over each denominator is a rational zero.... +/- 1/1, +/- 2/1, +/- 4/1, +/- 8/1, +/- 1/2, +/- 2/2, +/- 4/2, and +/- 8/2
Simplified: +/- 1, +/- 2, +/- 4, +/- 8, +/- 1/2, +/-1, +/- 2, and +/- 4
There are some duplicates so you can "drop" them... So your final answer is:
+/- 1/2, +/- 1, +/- 2, +/- 4, +/- 8

- anonymous

omg
this is so confusing

- anonymous

f(x) = -2x^4 + 4x^3 + 3x^2 + 18
constant term?
Factors of the leading coefficient?

- anonymous

http://softmath.com/tutorials-3/reducing-fractions/the-real-zeros-of-a-polynomial.html

- anonymous

factors of 2: 1,2
factors of 18: 1,2,3,4,6,18
so some examples include 1/1,1/2,2/1,2/2,3/1,3/2,...

- anonymous

ok

- anonymous

so what are constant term?
Factors of the leading coefficient?
and do i need to do that for every number?

- anonymous

@jenny1003

- anonymous

-2 and 18 Sorry I'm helping alot of ppl at the same time

- anonymous

factors of 2: 1,2
factors of 18: 1,2,3,4,6,18
factors of 4: 1,2,4
factors of 13: 1,3,

- anonymous

3 not 13

- anonymous

The leading term of a polynomial is the term of highest degree.
The leading coefficient of a polynomial is the coefficient of the leading term.
The degree of a polynomial is the degree of the leading term.

- anonymous

leading term 4
leading coefficient -2

- anonymous

I'm lost right now

- anonymous

i am too

- anonymous

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- anonymous

@200205650 Please help....Srry

- anonymous

http://www.mcg.net/nelson/CHAT/math/precalculus/overheads/sec.%202.5.pdf

- anonymous

So you are pretty much solving for x in this equation right?

- anonymous

i don't really know :O

- anonymous

@ParthKohli

- anonymous

http://www.virtualnerd.com/tutorials/?id=Alg2_06_01_0020

- anonymous

This video might help in solving this problem. And yes you are trying to find what are all the numbers that can equal x. Factoring is one way of solving this problem. I can help you if you don't know how to factor this problem.

- anonymous

@ganeshie8 @nincompoop

- anonymous

@Peaches15

- anonymous

@DanTheMan99

- anonymous

i just saw the video, but still i can't understand

- anonymous

Did you watch the whole thing?

- anonymous

yes

- anonymous

jk

- anonymous

i didn't

- anonymous

i saw the beginning

- anonymous

Okay why don't you watch that video and I'll try to solve this problem using factoring. Is that fine?

- anonymous

thank you

- anonymous

No problem!

- anonymous

@DanTheMan99 check this out
http://www.wolframalpha.com/input/?i=f%28x%29+%3D+-2x%5E4+%2B+4x%5E3+%2B+3x%5E2+%2B+18

- anonymous

\[-2x^4+4x^3+3x^2+18\]\[-2x^3(x-2)+3(x^2+6)\]\[(-2x^3+3)(x-2)(x^2+6)\]
Equation #1:\[(-2x^3+3)=0\]\[-2x^3=-3\]\[x^3=\frac{ 3 }{ 2 }\]\[x=0.72112\]
Equation#2: \[(x-2)=0\]\[x=2\]
Equation #3:\[(x^2+6)=0\]\[x^2=-6\]\[x=\sqrt{6}i\]

- anonymous

thank you guys so much

- anonymous

You're welcome!

- anonymous

Greatly done, @200205650

- anonymous

Thanks!

- anonymous

+ 1/2, + 1, + 2, + 4, + 8, - 1/2, - 1, - 2, - 4, and -8.

- anonymous

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- anonymous

i don't know how to answer

- anonymous

like how to put it into words

- anonymous

ugh

- anonymous

@nono266 please help me

- anonymous

##### 1 Attachment

- anonymous

what should i write

- OregonDuck

you have it written fine

- anonymous

i know
but whats my explanation

- anonymous

like what proof can i give

- OregonDuck

there is no need to do so

- anonymous

are you sure

- OregonDuck

100% positive

- OregonDuck

is this flvs?

- anonymous

yeah

- OregonDuck

ok then yeah you do not need to

- OregonDuck

for sure

- OregonDuck

it is fine if you have the right answer then they know you understand it

- anonymous

ok
thanks

- OregonDuck

do i get 10 owl bucks because i need them

- OregonDuck

?????????????

- OregonDuck

do you have paypal?

- anonymous

no

- OregonDuck

can you ask the question for me and i go under it. ask a qualified helper question

- OregonDuck

ask the question as ALGEBRA 1 HELP THEN I WILL ADD THE REST

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