madhu.mukherjee.946
  • madhu.mukherjee.946
a loan earns interest at a certain rate (compound)per cent per annum.four years ago the amount was rs.81 ;now it is rs.144.what will the amount be two years hence?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Use the formula and plug in the values.
anonymous
  • anonymous
\[A=P(1+\frac{ r }{ 100 })^n\]
madhu.mukherjee.946
  • madhu.mukherjee.946
dude i know the formula but this sum is different

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madhu.mukherjee.946
  • madhu.mukherjee.946
basically we neither have p value nor t nor r only we have is two compound interest amount
anonymous
  • anonymous
you have P, A and n
madhu.mukherjee.946
  • madhu.mukherjee.946
where do you see p and 81 and 144 are compound interest amount and not the total amount
anonymous
  • anonymous
it is the interest+year 0 p
madhu.mukherjee.946
  • madhu.mukherjee.946
u solve the problem if you can and pls give me the steps coz i can't
anonymous
  • anonymous
first rearrange the formula and put r to one side
anonymous
  • anonymous
\[144=81(1+\frac{ r }{ 100 })^4\] \[\frac{ 144 }{ 81 }=(1+\frac{ r }{ 100 })^4\]
anonymous
  • anonymous
\[\frac{ 16 }{ 9 } = (1+\frac{ r }{ 100 })^4\]
anonymous
  • anonymous
\[\frac{ 4 }{ 3 } = (1 + \frac{ r }{ 100 })^2\]
anonymous
  • anonymous
\[\frac{ 4 }{ 3 } = 1+ \frac{ r }{ 50 } + \frac{ r^2 }{ 10000 }\]\[-\frac{ 1 }{ 3 } = \frac{ r }{ 50 } + \frac{ r }{ 10000 }\]
madhu.mukherjee.946
  • madhu.mukherjee.946
i do not think this is ok...coz the answer given id 191.40
anonymous
  • anonymous
some typos there
madhu.mukherjee.946
  • madhu.mukherjee.946
ok thanks anyways
anonymous
  • anonymous
mines 15.47
madhu.mukherjee.946
  • madhu.mukherjee.946
no its 191.40
madhu.mukherjee.946
  • madhu.mukherjee.946
thanks for you try
anonymous
  • anonymous
the interest rate is 15.47
anonymous
  • anonymous
so the 2 years stuff its up to you to try
madhu.mukherjee.946
  • madhu.mukherjee.946
i'm so sorry saseal pls don't mind your calculation was absolutely correct .....i understood the sum a little later thanks dude thank you so much

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