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madhu.mukherjee.946
 one year ago
a loan earns interest at a certain rate (compound)per cent per annum.four years ago the amount was rs.81 ;now it is rs.144.what will the amount be two years hence?
madhu.mukherjee.946
 one year ago
a loan earns interest at a certain rate (compound)per cent per annum.four years ago the amount was rs.81 ;now it is rs.144.what will the amount be two years hence?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use the formula and plug in the values.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[A=P(1+\frac{ r }{ 100 })^n\]

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dude i know the formula but this sum is different

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0basically we neither have p value nor t nor r only we have is two compound interest amount

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0where do you see p and 81 and 144 are compound interest amount and not the total amount

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is the interest+year 0 p

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0u solve the problem if you can and pls give me the steps coz i can't

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first rearrange the formula and put r to one side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[144=81(1+\frac{ r }{ 100 })^4\] \[\frac{ 144 }{ 81 }=(1+\frac{ r }{ 100 })^4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 16 }{ 9 } = (1+\frac{ r }{ 100 })^4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4 }{ 3 } = (1 + \frac{ r }{ 100 })^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4 }{ 3 } = 1+ \frac{ r }{ 50 } + \frac{ r^2 }{ 10000 }\]\[\frac{ 1 }{ 3 } = \frac{ r }{ 50 } + \frac{ r }{ 10000 }\]

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0i do not think this is ok...coz the answer given id 191.40

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks anyways

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0no its 191.40

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0thanks for you try

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the interest rate is 15.47

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the 2 years stuff its up to you to try

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0i'm so sorry saseal pls don't mind your calculation was absolutely correct .....i understood the sum a little later thanks dude thank you so much
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