## madhu.mukherjee.946 one year ago a loan earns interest at a certain rate (compound)per cent per annum.four years ago the amount was rs.81 ;now it is rs.144.what will the amount be two years hence?

1. anonymous

Use the formula and plug in the values.

2. anonymous

$A=P(1+\frac{ r }{ 100 })^n$

dude i know the formula but this sum is different

basically we neither have p value nor t nor r only we have is two compound interest amount

5. anonymous

you have P, A and n

where do you see p and 81 and 144 are compound interest amount and not the total amount

7. anonymous

it is the interest+year 0 p

u solve the problem if you can and pls give me the steps coz i can't

9. anonymous

first rearrange the formula and put r to one side

10. anonymous

$144=81(1+\frac{ r }{ 100 })^4$ $\frac{ 144 }{ 81 }=(1+\frac{ r }{ 100 })^4$

11. anonymous

$\frac{ 16 }{ 9 } = (1+\frac{ r }{ 100 })^4$

12. anonymous

$\frac{ 4 }{ 3 } = (1 + \frac{ r }{ 100 })^2$

13. anonymous

$\frac{ 4 }{ 3 } = 1+ \frac{ r }{ 50 } + \frac{ r^2 }{ 10000 }$$-\frac{ 1 }{ 3 } = \frac{ r }{ 50 } + \frac{ r }{ 10000 }$

i do not think this is ok...coz the answer given id 191.40

15. anonymous

some typos there

ok thanks anyways

17. anonymous

mines 15.47

no its 191.40

thanks for you try

20. anonymous

the interest rate is 15.47

21. anonymous

so the 2 years stuff its up to you to try