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anonymous

  • one year ago

Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @nono266 @AnimalLover8 @mathmate @Frostbite @TheGaMer007

  3. anonymous
    • one year ago
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    @dan815

  4. anonymous
    • one year ago
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    sin x° = cos y° = Please Help, and what relationship they have?

  5. anonymous
    • one year ago
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    first use the Pythagorean theorem to find the hypotenuse of that triangle

  6. anonymous
    • one year ago
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    Im not sure how to do that?

  7. anonymous
    • one year ago
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    I forgot how to do that @nono266

  8. anonymous
    • one year ago
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    Can you please help me do this @nono266

  9. anonymous
    • one year ago
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    do you see the red little thing on the triangle?

  10. anonymous
    • one year ago
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    Yes

  11. anonymous
    • one year ago
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    The box?

  12. anonymous
    • one year ago
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    @nono266

  13. anonymous
    • one year ago
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    no the hypotenuse. the dotted line. okay so the Pythagorean theorem is pretty simple. a2 + b2 = c2 therefore; 15^2 + 8^2 = c^2 225 + 64 = 289 the sq root of 289 = 17 so c (the red dotted line aka hypotenuse) = 17

  14. anonymous
    • one year ago
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    So what does sin x° = and cos y° = and how are they related Im not understanding

  15. anonymous
    • one year ago
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    The definition of sin x is side opposite angle x/hypotenuse

  16. anonymous
    • one year ago
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    So this means what exactly

  17. anonymous
    • one year ago
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    What is the measure of the side that is opposite the angle whose measure is x degrees?

  18. anonymous
    • one year ago
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    I dont know @nono266 I just really need to know what sin x° = and cos y° = and what their relationship is I dont understand this stuff at all

  19. anonymous
    • one year ago
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    I just need the answer :(

  20. anonymous
    • one year ago
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    @nono266

  21. anonymous
    • one year ago
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    The relationship between sin x and cos y is that they are equal.

  22. anonymous
    • one year ago
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    and what do they equal

  23. anonymous
    • one year ago
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    I cant give out the answers as much so heres an exact problem on how to solve it sin = opposite/hypotenuse (SOH) cos = adjacent/hypotenuse (CAH) For x, the opposite side is 6 and the hypotenuse is 10: So sin x° is 6/10 = 3/5 For y, the adjacent side is also 6 and the hypotenuse is still 10: So cos y° is also 6/10 = 3/5 Answer: sin x° and cos y° = 3/5

  24. anonymous
    • one year ago
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    Thank you :)

  25. anonymous
    • one year ago
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    If you have questions regarding the process, feel free to ask. If not I hope you ace this! Good luck!

  26. anonymous
    • one year ago
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    @nono266 how do I find the hypotenuse cx

  27. anonymous
    • one year ago
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    and would opposite be 8?

  28. anonymous
    • one year ago
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    the hypotenuse is 17 opposite for x; 8 opposite for y ; 15

  29. anonymous
    • one year ago
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    Thank you so much :D

  30. anonymous
    • one year ago
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    You better ace this

  31. anonymous
    • one year ago
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    Lol I'll try my best

  32. anonymous
    • one year ago
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    This is the first concept I actually am learning in Geometry, Idk how I've even been passing the year XD

  33. anonymous
    • one year ago
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    |dw:1438707923360:dw|

  34. anonymous
    • one year ago
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    YES XD THANK YOU LMAO SO DAMN TRUE

  35. anonymous
    • one year ago
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    Wait Whats the Adjacent for Y?

  36. anonymous
    • one year ago
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    adjacent means next to

  37. anonymous
    • one year ago
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    I got 0.471 to the nearest thousandth for 8/17

  38. anonymous
    • one year ago
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    but I got 0.882 to the nearest thousandth for 15/17

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