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anonymous

  • one year ago

What is the remainder of (2x3 − 18x + 5) ÷ (x − 3)? -5 5 2 3

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  1. anonymous
    • one year ago
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    @Peaches15 can you help?

  2. anonymous
    • one year ago
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    4

  3. Nnesha
    • one year ago
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    x-5=0 solve for x and the substitute x in this 2x^3 − 18x + 5 equation for its value

  4. Nnesha
    • one year ago
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    or you can apply synthetic division

  5. sohailiftikhar
    • one year ago
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    it should be -5

  6. anonymous
    • one year ago
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    -5 is wrong i got it wrong the last time i tried it

  7. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha x-5=0 solve for x and the substitute x in this 2x^3 − 18x + 5 equation for its value \(\color{blue}{\text{End of Quote}}\) correction: x-3=0

  8. anonymous
    • one year ago
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    would it be 3?

  9. sohailiftikhar
    • one year ago
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    ok clarify your equation 2x3 or 2x^3

  10. sohailiftikhar
    • one year ago
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    solve for this x-3=0 then x=3 put value of x in equation you will get answer

  11. anonymous
    • one year ago
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    sorry its 2x^3

  12. Nnesha
    • one year ago
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    yep so now substitute al x for 3\[\huge\rm 2(3)^3-18(3)+5= ??\]

  13. sohailiftikhar
    • one year ago
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    it's 5

  14. anonymous
    • one year ago
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    so 2-18+5=-11

  15. sohailiftikhar
    • one year ago
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    lol nah put value of x

  16. sohailiftikhar
    • one year ago
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    you will get 54-54+5=5

  17. Nnesha
    • one year ago
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    no substitute x for 3 just replace x

  18. anonymous
    • one year ago
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    oh okay i think i get it now

  19. Nnesha
    • one year ago
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    x for 3\[\huge\rm 2(\color{reD}{3})^3-18(\color{reD}{3})+5= ??\]

  20. sohailiftikhar
    • one year ago
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    when you are given like that divided by x-5 or x-3 etc then just put it equal to zero and get value of x put this value in equation you will get your answer

  21. sohailiftikhar
    • one year ago
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    good job Nnesha

  22. Nnesha
    • one year ago
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    or if you want to apply synthetic division then you need to write highest degree to smallest |dw:1438707198108:dw| 0 for 0x^2 it's not in the equation but we still have to write highest degree to smallest x^3,x^2 and then x

  23. Nnesha
    • one year ago
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    thanks.

  24. sohailiftikhar
    • one year ago
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    np

  25. Nnesha
    • one year ago
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    lol

  26. anonymous
    • one year ago
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    thanks

  27. Nnesha
    • one year ago
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    my pleasure

  28. sohailiftikhar
    • one year ago
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    welcome

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