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anonymous

  • one year ago

Please help... Thanks! Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats. 1. What is the theoretical probability that the family has two dogs or two cats?

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  1. anonymous
    • one year ago
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    @kitty_lover1234

  2. anonymous
    • one year ago
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    @DanJS

  3. welshfella
    • one year ago
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    draw a tree diagram |dw:1438709422886:dw|

  4. anonymous
    • one year ago
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    what??

  5. welshfella
    • one year ago
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    P (2 cats) = 0.5*0.5

  6. anonymous
    • one year ago
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    0.25

  7. welshfella
    • one year ago
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    |dw:1438709623610:dw|

  8. welshfella
    • one year ago
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    Going along the cat / cat branch we multutiply 0.5 by 0.5 to get P = 0.25 or 25%

  9. anonymous
    • one year ago
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    sooooo....

  10. welshfella
    • one year ago
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    P(2 dogs) = 0.25 also

  11. anonymous
    • one year ago
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    yes

  12. welshfella
    • one year ago
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    P(cat and dog) follows 2 paths so its 0.25 + 0.25 = 0.5

  13. anonymous
    • one year ago
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    i dont understand what is the answer

  14. welshfella
    • one year ago
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    |dw:1438709856132:dw|

  15. anonymous
    • one year ago
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    So what is the answer

  16. welshfella
    • one year ago
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    Probability of 2 cats or 2 dogs = 0.25 + 0.25 = 0.50 or 50%

  17. anonymous
    • one year ago
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    oh pellet i read it wromg this is actually so simple

  18. welshfella
    • one year ago
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    going along the branches you multiply the probabilities If its a choice of one branch OR the other you ADD the probabilities

  19. anonymous
    • one year ago
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    OMG im dying i wrote s h i t and when i npressed post it spell corrected to pellet

  20. welshfella
    • one year ago
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    is that right!!?? lol

  21. anonymous
    • one year ago
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    ya try it

  22. welshfella
    • one year ago
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    pellet

  23. anonymous
    • one year ago
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    no do it all together

  24. anonymous
    • one year ago
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    HAHAH see

  25. welshfella
    • one year ago
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    lol yea

  26. anonymous
    • one year ago
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    well thanks

  27. welshfella
    • one year ago
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    yw

  28. anonymous
    • one year ago
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    can yyou helpme with another one

  29. anonymous
    • one year ago
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    ????

  30. welshfella
    • one year ago
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    one thing worth remembering with probabilities is AND = * and OR = + cat AND cat = * , 2 dogs OR 2 cats = +

  31. welshfella
    • one year ago
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    ok

  32. anonymous
    • one year ago
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    ok

  33. anonymous
    • one year ago
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    2. Describe how to use two coins to simulate which two pets the family has. 3. Flip both coins 50 times and record your data in a table like the one below.

  34. anonymous
    • one year ago
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    it still has to do with the first question

  35. welshfella
    • one year ago
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    let cats = heads and dog = tails - toss the coin. This is similar to to the question because there is an equally likely chance to get a head as a tail.

  36. welshfella
    • one year ago
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    * toss the 2 coins

  37. anonymous
    • one year ago
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    but it says 2 coins

  38. welshfella
    • one year ago
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    yea - you will toss 2 coins together or one after the other that does noy matter

  39. anonymous
    • one year ago
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    oh huh ok

  40. anonymous
    • one year ago
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    thx

  41. welshfella
    • one year ago
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    yw

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