anonymous
  • anonymous
What are the roots of 2x+6=−5x? 3−+i2 −3−+i2 −3−+2i4 3−+i2‾‾√4 please help
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
@t.ashleyxx
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
mathstudent55
  • mathstudent55
Shouldn't one of the x's be squared?
anonymous
  • anonymous
ill attach a screenshot it doesn't post right
anonymous
  • anonymous
anonymous
  • anonymous
mathstudent55
  • mathstudent55
That's a completely different problem.
anonymous
  • anonymous
can you help?
mathstudent55
  • mathstudent55
With the screenshot?
anonymous
  • anonymous
yes
mathstudent55
  • mathstudent55
We need to multiply this together. \((1 + i\sqrt 3)(1 + 2i\sqrt 3) \) We use FOIL. \(=1 + 2i\sqrt 3 + i \sqrt 3 + 2i^2 (\sqrt 3)^2\) Ok so far?
mathstudent55
  • mathstudent55
\(=1 + 3i\sqrt 3 - 6\) \(=-5 + 3i\sqrt 3 \)
anonymous
  • anonymous
okay

Looking for something else?

Not the answer you are looking for? Search for more explanations.