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anonymous

  • one year ago

how do i solve the equation by completing the square for x^2+6x=-8 with steps please

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  1. IrishBoy123
    • one year ago
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    \(x^2+6x=-8\) first, can you write it as: \("something" \ = 0\)

  2. IrishBoy123
    • one year ago
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    where "something" has your various terms in it!

  3. anonymous
    • one year ago
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    wait what

  4. IrishBoy123
    • one year ago
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    can you make the RHS of your equation equal to zero

  5. anonymous
    • one year ago
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    what is that?

  6. IrishBoy123
    • one year ago
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    let's say i have : \(x^2+4x=−10\) i can then say that: \(x^2+4x \ + 10=−10 \ + \ 10\) \(x^2+4x + 10 = 0\) then i am good to go can tou do that with your equation?

  7. anonymous
    • one year ago
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    okay thanks

  8. anonymous
    • one year ago
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    wait what about the 4

  9. IrishBoy123
    • one year ago
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    what 4 ?

  10. anonymous
    • one year ago
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    wait 6x i meant

  11. IrishBoy123
    • one year ago
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    OK, we can complete the square without fiddling around with your equation so \(x^2+6x=-8\) look only at the L.H.S (left hand side): \(x^2+6x= (x + A)^2 - B\)

  12. anonymous
    • one year ago
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    wait is a and b the solution?

  13. IrishBoy123
    • one year ago
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    you will need A and B in the solution tracking back, you asked : "how do i solve the equation by completing the square for x^2+6x=-8 with steps please " that is a very reasonable question. do you know how to complete a square?

  14. anonymous
    • one year ago
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    no lol i got a 15 percent on my test and can not get it for the life of me

  15. IrishBoy123
    • one year ago
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    crumbs :-( what is \((x + 3)^2\) can you evaluate that?

  16. anonymous
    • one year ago
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    isit like (x+3) and (x-3)

  17. IrishBoy123
    • one year ago
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    crumbs almighty!! am i actually helping you or hindering you?!?! i do wonder !! \((x+3)^2 = (x+3)(x+3) = ....\)

  18. anonymous
    • one year ago
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    both sorta

  19. IrishBoy123
    • one year ago
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    ok love the directness!! am i now defunct?

  20. anonymous
    • one year ago
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    no sorry i was going somewhere

  21. IrishBoy123
    • one year ago
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    are we still going ???

  22. anonymous
    • one year ago
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    wait so i would add 8 to -8 and it would make it zero?

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