If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below. 17 23 −17 −23

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below. 17 23 −17 −23

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

For a compound function like that,, figure the innermost one out first, then use that value and move outwards
what is j(2) = ?
to be honest i have no clue @DanJS

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

-4? or 4?
j(x) = -2x j(2) = -2 * 2 = -4
Now to calculate h[j(2)] ... you use that value for j(2), for x in h
h( - 4) = ...
Yay! I got it right (Sort of) and how would you find h(-4)
if h(x) = 5x-3 then h(-4) = 5*(-4) -3 = -20 - 3 = -23
for those, work the inner function first, then keep using those output values and work outwards to the next function like we did
ok so am i done or i shtere more to go ?
that is it, you figured the inner function out, which was -4, then you use that value in the outer function h(-4) that is it
sp the answer is -23 ? @DanJS
*so
and if it is ty so much :) @DanJS
yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question