anonymous
  • anonymous
How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
please help me!! @jcoury @OregonDuck
OregonDuck
  • OregonDuck
what do you think?
anonymous
  • anonymous
im not sure!! like idk how to even solve for it. thats what i need help with.

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More answers

OregonDuck
  • OregonDuck
60 is the answer
OregonDuck
  • OregonDuck
it seems endless though lol :)
anonymous
  • anonymous
are you serious??!! how do you know this stuff??! lol.
OregonDuck
  • OregonDuck
i may be wrong am i @kropot72 ?
kropot72
  • kropot72
There are 6 choices for the first selection. Having chosen one number there are 5 choices for the second number, 4 choices for the third and 3 choices for the fourth. Therefore the number of four digit numbers is given by: \[\large 6\times5\times4\times3=you\ can\ calculate\]
anonymous
  • anonymous
360?! yess thats an option! thankyou!
kropot72
  • kropot72
You're welcome :)
OregonDuck
  • OregonDuck
360 is correct
anonymous
  • anonymous
shouldn't it be 6*5*4*3*2?
OregonDuck
  • OregonDuck
never doubt a champ
kropot72
  • kropot72
@niels5x9 Why do you think that?
anonymous
  • anonymous
because first you have six options then you have five options then four then three and finally two right?
anonymous
  • anonymous
oh oops 4 digit numbers i faileded
kropot72
  • kropot72
Never mind :)

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