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anonymous

  • one year ago

How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

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  1. anonymous
    • one year ago
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    please help me!! @jcoury @OregonDuck

  2. OregonDuck
    • one year ago
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    what do you think?

  3. anonymous
    • one year ago
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    im not sure!! like idk how to even solve for it. thats what i need help with.

  4. OregonDuck
    • one year ago
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    60 is the answer

  5. OregonDuck
    • one year ago
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    it seems endless though lol :)

  6. anonymous
    • one year ago
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    are you serious??!! how do you know this stuff??! lol.

  7. OregonDuck
    • one year ago
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    i may be wrong am i @kropot72 ?

  8. kropot72
    • one year ago
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    There are 6 choices for the first selection. Having chosen one number there are 5 choices for the second number, 4 choices for the third and 3 choices for the fourth. Therefore the number of four digit numbers is given by: \[\large 6\times5\times4\times3=you\ can\ calculate\]

  9. anonymous
    • one year ago
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    360?! yess thats an option! thankyou!

  10. kropot72
    • one year ago
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    You're welcome :)

  11. OregonDuck
    • one year ago
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    360 is correct

  12. anonymous
    • one year ago
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    shouldn't it be 6*5*4*3*2?

  13. OregonDuck
    • one year ago
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    never doubt a champ

  14. kropot72
    • one year ago
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    @niels5x9 Why do you think that?

  15. anonymous
    • one year ago
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    because first you have six options then you have five options then four then three and finally two right?

  16. anonymous
    • one year ago
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    oh oops 4 digit numbers i faileded

  17. kropot72
    • one year ago
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    Never mind :)

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