Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. a(n) -6 + (n - 1) (6)

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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. a(n) -6 + (n - 1) (6)

Algebra
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0, -18 and -54
dude there is no -18 -54 as an answer only thing near that is 18 54
please explain

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Other answers:

–6, 12, 48 –6, 18, 54 0, 18, 54 6, 18, 54 thats the possable outcomes
plug in n = 1 and see what you get
then you do 1-1 so thats 0
a1 = -6 + (1-1)d
* thats 6 not d
ya
ok so the correct answer is D?
so whata the first term?
dude i really think my answer is correct you just do the previous answer -6 every time n goes up 1
first term = -6 + 0*6 = -6
Wait the correct one is B
and what was answer B?
second = -6 + (2-1)*6 = ?
4th term = -6 +3*6 = 12
ok
10th = -6 + (10-1)*6 = -6 + 9*6 = ?
54
No -6 + 54 = ?
48
right A is the correct option
thanks so much i fanned you:)
ty yw

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