@jenny1003

- help_people

@jenny1003

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

Yea? I was about to eat lol

- anonymous

@he

- anonymous

@help_people

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Let see what it is

- help_people

are yu still here?

- help_people

@jenny1003

- anonymous

YEA

- anonymous

@help_people

- help_people

@jenny1003

- anonymous

Yea

- Astrophysics

What about 4xy+7?

- anonymous

There is no like terms so it would jus be 4xy+7

- Astrophysics

Can you please specify your question..

- help_people

what is the degree of 4xy+7

- anonymous

It would be constant I think because you have no exponents

- anonymous

Or quadratic function

- help_people

it is a first degree trinomial right?

- Astrophysics

|dw:1438722533831:dw| the degree is the largest exponent in the variable but since there are two variables with this coefficient which are both to the power of 1, it will have a degree of 2.

- help_people

so is it a monomial binomial trinomial

- Astrophysics

\[x = x^1 \] when it doesn't show a exponent it means 1

- anonymous

binomial

- help_people

hello?

- Astrophysics

exponent of 1*

- help_people

your are not understanding what i am asking is it a trinomial binomial or monomial

- Astrophysics

I do understand what you want, but you're just looking for answers rather than understanding the question.
Monomial = 1 term
Binomial = 2 terms
trinomial = 3 terms

- anonymous

I think it's binomal

- Astrophysics

Look at my drawing and you will know.

- help_people

ok i am thinking it is a 2nd degree binomial

- Astrophysics

Yup

- anonymous

Yea

- help_people

ok i am going to post on another tab so you can help with another one please?

- help_people

actualy acouple

- anonymous

Any other question ?

- anonymous

Ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.