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anonymous
 one year ago
Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC.
Which of these could be a step to prove that BC^2 = AB^2 + AC^2?
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus BD.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus BD.
anonymous
 one year ago
Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC^2 = AB^2 + AC^2? By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus AB. By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus BD. By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus AB. By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus BD.

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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/study#/updates/4fbf9fede4b0964abc821e39

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No offense but I hate when people give me links. I read all links before I ask a question. If I ask the question that means I don't understand the explanation in the link. So please....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@princeharryyy @Prosper2win @PrinceKel @abb0t @veedotvee @Compassionate @nincompoop

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @IrishBoy123 @taramgrant0543664

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you aren't going to help please do not spam my question @automaticloveletter

automaticloveletter
 one year ago
Best ResponseYou've already chosen the best response.0I just gave you good luck since I can't help you, that isn't spam.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nvm, it was a diff prob my bad

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 we need help because this is confusing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well I guessed and got it wrong. It is not D.

dessyj1
 one year ago
Best ResponseYou've already chosen the best response.1Would you like to know why?
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