Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC.
Which of these could be a step to prove that BC^2 = AB^2 + AC^2?
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus BD.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus BD.

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- anonymous

- anonymous

No offense but I hate when people give me links. I read all links before I ask a question. If I ask the question that means I don't understand the explanation in the link. So please....

- anonymous

:| <---- my face rn

- anonymous

- automaticloveletter

Good luck

- anonymous

Wdym good luck?

- anonymous

If you aren't going to help please do not spam my question @automaticloveletter

- automaticloveletter

I just gave you good luck since I can't help you, that isn't spam.

- anonymous

i got it

- anonymous

What is it?

- anonymous

nvm, it was a diff prob my bad

- anonymous

@ganeshie8 we need help because this is confusing

- anonymous

Well I guessed and got it wrong. It is not D.

- dessyj1

It is B

- dessyj1

Would you like to know why?

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