• anonymous
Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC^2 = AB^2 + AC^2? By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus AB. By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus BD. By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus AB. By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus BD.
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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