Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC.
Which of these could be a step to prove that BC^2 = AB^2 + AC^2?
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus BD.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus BD.

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