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anonymous
 one year ago
What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9?
(−2, 4)
(−1, 7)
(1, 15)
(2, 9)
anonymous
 one year ago
What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9? (−2, 4) (−1, 7) (1, 15) (2, 9)

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2formula to find x coordinate of vertex \[\huge\rm x=\frac{ b }{ 2a }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2then substitute all x in f(x) equation for its value to find ycoordinate of vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do i put for the a and b?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2a=leading coefficient b=middle term \[\huge\rm \color{reD}{A}x^2+\color{blue}{B}x+C=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i leave the negative sign in front of the b even when it's a positive?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes b is positive but negative is in the formula so that stays there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be \[x=\frac{ 4 }{ 2(2)}\]?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 4/4 and i would just divide it and it would come out as 1 right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes that's xcoordinate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i find the ycoordinate now?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2now to find y coordinate substitute x for 1 \[\rm \color{reD}{x=1}\] \[\huge\rm 2\color{reD}{x}^2+4\color{red}{x}+9=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the ycoordinate would be 3? (1,3)?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2when you take square of negative number you will get positive number

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm 2\color{reD}{(1)}^2+4\color{red}{(1)}+9=0\] now solve (1)^2 is same as 1 times 1 = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes 1 times 1 = 1 (1)^2=1 so solve \[\huge\rm 2\color{reD}{(1)}+4\color{red}{(1)}+9=?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could you help me out with another one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1? f(x) = −one fourth (x − 5)2 + 1 f(x) = one fourth (x − 5)2 + 1 f(x) = −one fourth (x − 5)2 f(x) = one fourth (x − 5)2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well not sure about this need to review this stuff hmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its fine. i got it Cx thank you tho !
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