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anonymous
 one year ago
What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1?
f(x) = −one fourth (x − 5)2 + 1
f(x) = one fourth (x − 5)2 + 1
f(x) = −one fourth (x − 5)2
f(x) = one fourth (x − 5)2
anonymous
 one year ago
What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1? f(x) = −one fourth (x − 5)2 + 1 f(x) = one fourth (x − 5)2 + 1 f(x) = −one fourth (x − 5)2 f(x) = one fourth (x − 5)2

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freckles
 one year ago
Best ResponseYou've already chosen the best response.3i like to draw first... dw:1438724043667:dw the vertex will be halfway between the directrix and the focus

freckles
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438724120865:dw what are the coordinates for V

freckles
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438724184117:dw but isn't (0,5) on the yaxis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk that's why im asking you i have no idea how to do any of this CX

freckles
 one year ago
Best ResponseYou've already chosen the best response.3so you haven't ever plotted points in your class?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have but i never actually paid attention. im one of those kids that sleep in class tbh . and now im making up for it :/

freckles
 one year ago
Best ResponseYou've already chosen the best response.3(x,y) means we are going to travel horizontal x units (note: the sign of x tells us which way we will travel horizontally) means we are going to travel vertically y units (note: the sign of y tells which way we will travel vertically)

freckles
 one year ago
Best ResponseYou've already chosen the best response.3(0,5) tells us we will go 0 units left or right horizontally tells us we will go 5 units up

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so we would be going (5,0) ? Because you're going 5 units to the right and 0 up ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do i do with that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0p.s im also really bad at graphing even if i was good at algebra CX

freckles
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438724452936:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.3(5,1) is the focus you were given this y=1 is the directrix (5,0) is what you found to be the vertex and we just determined p was negative since the parabola is opened down you can find the other part of p by finding the vertical distance between the vertex and the dirextrix which is 1 so p=1 since we determined it was going to be negative already \[(xh)^2=4p(yk) \\ \text{ divide } 4p \text{ on both sides } \frac{1}{4p}(xh)^2=yk \\ \text{ add } k \text{ on both sides } \\ y=\frac{1}{4p}(xh)^2+k\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3you have already determined the vertex (h,k) was (5,0) and you have determined p is 1 input values and you are done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0isn'y y 1 @freckles

freckles
 one year ago
Best ResponseYou've already chosen the best response.3x and y are variables

freckles
 one year ago
Best ResponseYou've already chosen the best response.3you found (h,k) is (5,0) replace h with 5 replace k with 0 you found p=1 replace p with 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0god im so confused :

freckles
 one year ago
Best ResponseYou've already chosen the best response.3x and y are variables

freckles
 one year ago
Best ResponseYou've already chosen the best response.3can you replace h and k and p with what we have found?
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