anonymous
  • anonymous
What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1? f(x) = −one fourth (x − 5)2 + 1 f(x) = one fourth (x − 5)2 + 1 f(x) = −one fourth (x − 5)2 f(x) = one fourth (x − 5)2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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freckles
  • freckles
i like to draw first... |dw:1438724043667:dw| the vertex will be halfway between the directrix and the focus
freckles
  • freckles
|dw:1438724120865:dw| what are the coordinates for V
anonymous
  • anonymous
(0,5)?

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freckles
  • freckles
|dw:1438724184117:dw| but isn't (0,5) on the y-axis
anonymous
  • anonymous
idk that's why im asking you i have no idea how to do any of this CX
freckles
  • freckles
so you haven't ever plotted points in your class?
anonymous
  • anonymous
i have but i never actually paid attention. im one of those kids that sleep in class tbh . and now im making up for it :/
freckles
  • freckles
(x,y) means we are going to travel horizontal x units (note: the sign of x tells us which way we will travel horizontally) means we are going to travel vertically y units (note: the sign of y tells which way we will travel vertically)
freckles
  • freckles
(0,5) tells us we will go 0 units left or right horizontally tells us we will go 5 units up
anonymous
  • anonymous
oh so we would be going (5,0) ? Because you're going 5 units to the right and 0 up ?
freckles
  • freckles
right
freckles
  • freckles
the vertex is (5,0)
anonymous
  • anonymous
what do i do with that?
anonymous
  • anonymous
p.s im also really bad at graphing even if i was good at algebra CX
freckles
  • freckles
|dw:1438724452936:dw|
anonymous
  • anonymous
so (5,-1)?
freckles
  • freckles
(5,-1) is the focus you were given this y=1 is the directrix (5,0) is what you found to be the vertex and we just determined p was negative since the parabola is opened down you can find the other part of p by finding the vertical distance between the vertex and the dirextrix which is 1 so p=-1 since we determined it was going to be negative already \[(x-h)^2=4p(y-k) \\ \text{ divide } 4p \text{ on both sides } \frac{1}{4p}(x-h)^2=y-k \\ \text{ add } k \text{ on both sides } \\ y=\frac{1}{4p}(x-h)^2+k\]
freckles
  • freckles
you have already determined the vertex (h,k) was (5,0) and you have determined p is -1 input values and you are done
anonymous
  • anonymous
would x =-1?
anonymous
  • anonymous
isn'y y -1 @freckles
anonymous
  • anonymous
isn't*
freckles
  • freckles
x and y are variables
freckles
  • freckles
you found (h,k) is (5,0) replace h with 5 replace k with 0 you found p=-1 replace p with -1
anonymous
  • anonymous
what is x and y?
anonymous
  • anonymous
god im so confused :|
anonymous
  • anonymous
or nahh XD im dead
freckles
  • freckles
x and y are variables
freckles
  • freckles
can you replace h and k and p with what we have found?

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