if 2/3 p + 6 =7/6 p , what is p?

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if 2/3 p + 6 =7/6 p , what is p?

Mathematics
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bring p to 1side of the equation and solve
hint: subtract 2/3p from both side of the equation
so we have 6=7/6p-2/3p

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hint: multiply both sides by "p"
r u guys sure?
@jdoe0001 u r wrong
if we follow what @lynfran stated we can arrive at the answer
hmm? is the fellow even here? he doesn't seem to be saying anything
idk
\[\frac{ 2 }{ 3p }+6=\frac{ 7 }{ 6p }\]\[6=\frac{ 7 }{ 6p }-\frac{ 2 }{ 3p }\]\[6=\frac{ 7-4 }{ 6p }\]\[6=\frac{ 3 }{ 6p }\]\[6=\frac{ 1 }{ 2p }\]multiply both side by 2p we get \[2p*6=1\]\...solve for p..
@LynFran woudnt it be like this? \[\frac{ 2 }{ 3 }p+6=\frac{ 7 }{ 6 }\] \[6=\frac{ 7 }{ 6 }p-\frac{ 2 }{ 3 }p\] (you subtract 7/6 - 2/3 and get 1/2 ) \[6=\frac{ 1 }{ 2 }p\] \[p=?\]
no... then u will have p = 12 thats not the answer...lol
no?
continue frm where i left off 2p*6=1 12p=1 divide both sides by 12 to get the value of p...
ok
but that would not check out right. you would get, if you plug in 1/12 in for p, 109/18 = 7/72. wheras if you plug in 12 (the answer that i got ) you would get 14 = 14 clearly checking out.
or am i missing something?
\[\frac{ 2 }{ 3(\frac{ 1 }{ 12 }) }+6=?\]
14
what ???
\[\frac{ 7 }{ 6(\frac{ 1 }{ 12 }) }=?\]
ok idk how you did that
lol..
but then woudnt that mean that im also right?
couse idk what i did wrong
ok lets check...\[\frac{ 2 }{ 3(12) }+6=?\]\[\frac{ 7 }{ 6(12) }=?\]
u was suppose to find a common denominator \[\frac{ 7 }{ 6p }-\frac{ 2 }{ 3p }\]
wasnt the question \[\frac{ 2 }{ 3 }P+6=\frac{ 7 }{ 6 }P\] but you solved for \[\frac{ 2 }{ 3P }+6=\frac{ 7 }{ 6p }\]
isnt there a differance?
so \[\frac{ (7*1)-(2*2) }{ 6p }\]
\[\frac{ 1 }{ 2p }\]
and remember p" is in the denominator so we multiply by 2p to both sides of equation
so 2p*6=1
but in the original problem how do we know that the p was on the denominator?
well it looked so to me lol...could be wrong then...
if its not then ur right..
i understand what you were doing tho
ok..
but tylerhuang is offline hmm...

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