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anonymous

  • one year ago

if 2/3 p + 6 =7/6 p , what is p?

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  1. LynFran
    • one year ago
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    bring p to 1side of the equation and solve

  2. LynFran
    • one year ago
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    hint: subtract 2/3p from both side of the equation

  3. LynFran
    • one year ago
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    so we have 6=7/6p-2/3p

  4. jdoe0001
    • one year ago
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    hint: multiply both sides by "p"

  5. anonymous
    • one year ago
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    r u guys sure?

  6. anonymous
    • one year ago
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    @jdoe0001 u r wrong

  7. anonymous
    • one year ago
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    if we follow what @lynfran stated we can arrive at the answer

  8. jdoe0001
    • one year ago
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    hmm? is the fellow even here? he doesn't seem to be saying anything

  9. anonymous
    • one year ago
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    idk

  10. LynFran
    • one year ago
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    \[\frac{ 2 }{ 3p }+6=\frac{ 7 }{ 6p }\]\[6=\frac{ 7 }{ 6p }-\frac{ 2 }{ 3p }\]\[6=\frac{ 7-4 }{ 6p }\]\[6=\frac{ 3 }{ 6p }\]\[6=\frac{ 1 }{ 2p }\]multiply both side by 2p we get \[2p*6=1\]\...solve for p..

  11. anonymous
    • one year ago
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    @LynFran woudnt it be like this? \[\frac{ 2 }{ 3 }p+6=\frac{ 7 }{ 6 }\] \[6=\frac{ 7 }{ 6 }p-\frac{ 2 }{ 3 }p\] (you subtract 7/6 - 2/3 and get 1/2 ) \[6=\frac{ 1 }{ 2 }p\] \[p=?\]

  12. anonymous
    • one year ago
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    @LynFran

  13. LynFran
    • one year ago
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    no... then u will have p = 12 thats not the answer...lol

  14. anonymous
    • one year ago
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    no?

  15. LynFran
    • one year ago
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    continue frm where i left off 2p*6=1 12p=1 divide both sides by 12 to get the value of p...

  16. anonymous
    • one year ago
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    ok

  17. anonymous
    • one year ago
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    but that would not check out right. you would get, if you plug in 1/12 in for p, 109/18 = 7/72. wheras if you plug in 12 (the answer that i got ) you would get 14 = 14 clearly checking out.

  18. anonymous
    • one year ago
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    or am i missing something?

  19. LynFran
    • one year ago
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    \[\frac{ 2 }{ 3(\frac{ 1 }{ 12 }) }+6=?\]

  20. anonymous
    • one year ago
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    14

  21. anonymous
    • one year ago
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    what ???

  22. LynFran
    • one year ago
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    \[\frac{ 7 }{ 6(\frac{ 1 }{ 12 }) }=?\]

  23. anonymous
    • one year ago
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    ok idk how you did that

  24. LynFran
    • one year ago
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    lol..

  25. anonymous
    • one year ago
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    but then woudnt that mean that im also right?

  26. anonymous
    • one year ago
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    couse idk what i did wrong

  27. LynFran
    • one year ago
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    ok lets check...\[\frac{ 2 }{ 3(12) }+6=?\]\[\frac{ 7 }{ 6(12) }=?\]

  28. LynFran
    • one year ago
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    u was suppose to find a common denominator \[\frac{ 7 }{ 6p }-\frac{ 2 }{ 3p }\]

  29. anonymous
    • one year ago
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    wasnt the question \[\frac{ 2 }{ 3 }P+6=\frac{ 7 }{ 6 }P\] but you solved for \[\frac{ 2 }{ 3P }+6=\frac{ 7 }{ 6p }\]

  30. anonymous
    • one year ago
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    isnt there a differance?

  31. LynFran
    • one year ago
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    so \[\frac{ (7*1)-(2*2) }{ 6p }\]

  32. anonymous
    • one year ago
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    \[\frac{ 1 }{ 2p }\]

  33. LynFran
    • one year ago
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    and remember p" is in the denominator so we multiply by 2p to both sides of equation

  34. LynFran
    • one year ago
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    so 2p*6=1

  35. anonymous
    • one year ago
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    but in the original problem how do we know that the p was on the denominator?

  36. LynFran
    • one year ago
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    well it looked so to me lol...could be wrong then...

  37. LynFran
    • one year ago
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    if its not then ur right..

  38. anonymous
    • one year ago
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    i understand what you were doing tho

  39. LynFran
    • one year ago
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    ok..

  40. LynFran
    • one year ago
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    but tylerhuang is offline hmm...

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