A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
helpppppppp please.
anonymous
 one year ago
helpppppppp please.

This Question is Closed

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0What do you want to do with that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplify the trigonometric expression. Show your work.

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0if you want to combine the two fractions, need to multiply by a common denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay... idk how to do that?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0\[[\frac{ 1 }{ 1+\sin \theta }+\frac{ 1 }{ 1\sin \theta }]*\frac{ (1+\sin \theta)(1\sin \theta) }{ (1+\sin \theta)(1\sin \theta) }\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0Just multiplying the whole thing by 1... a ratio of something over itself

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay.. what does sin o stand for?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it kinda like pi=3.14? does it stand for a number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u do it step by step and explain..

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf \cfrac{1}{1+sin(\theta)}+\cfrac{1}{1sin(\theta)}\impliedby LCD\to [1+sin(\theta)][1sin(\theta)] \\ \quad \\ \cfrac{(1sin(\theta))+(1+sin(\theta))}{[1+sin(\theta)][1sin(\theta)]}\implies \cfrac{1\cancel{sin(\theta)}+1\cancel{+sin(\theta)}}{[1+sin(\theta)][1sin(\theta)]} \\ \quad \\ \\ \textit{difference of squares} \\ \quad \\ (ab)(a+b) = a^2b^2\qquad \qquad a^2b^2 = (ab)(a+b)\qquad thus\\  \\ \quad \\ \cfrac{1\cancel{sin(\theta)}+1\cancel{+sin(\theta)}}{{\color{brown}{ [1^2sin^2(\theta)] }}}\implies \cfrac{2}{{\color{brown}{ cos^2(\theta)}}} \\ \quad \\ 2\cdot \cfrac{1}{cos^2(\theta)}\implies 2sec^2(\theta)\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1the denominator is combined, since it's just a difference of squares and keep in mind that \(\bf sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)={\color{brown}{ 1cos^2(\theta)}}\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1woops, darn that came out off lemme redo that

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)={\color{brown}{ 1sin^2(\theta)}}\) rather
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.