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anonymous
 one year ago
helpppppppp please.
anonymous
 one year ago
helpppppppp please.

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.0What do you want to do with that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplify the trigonometric expression. Show your work.

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0if you want to combine the two fractions, need to multiply by a common denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay... idk how to do that?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0\[[\frac{ 1 }{ 1+\sin \theta }+\frac{ 1 }{ 1\sin \theta }]*\frac{ (1+\sin \theta)(1\sin \theta) }{ (1+\sin \theta)(1\sin \theta) }\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0Just multiplying the whole thing by 1... a ratio of something over itself

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay.. what does sin o stand for?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it kinda like pi=3.14? does it stand for a number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u do it step by step and explain..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \cfrac{1}{1+sin(\theta)}+\cfrac{1}{1sin(\theta)}\impliedby LCD\to [1+sin(\theta)][1sin(\theta)] \\ \quad \\ \cfrac{(1sin(\theta))+(1+sin(\theta))}{[1+sin(\theta)][1sin(\theta)]}\implies \cfrac{1\cancel{sin(\theta)}+1\cancel{+sin(\theta)}}{[1+sin(\theta)][1sin(\theta)]} \\ \quad \\ \\ \textit{difference of squares} \\ \quad \\ (ab)(a+b) = a^2b^2\qquad \qquad a^2b^2 = (ab)(a+b)\qquad thus\\  \\ \quad \\ \cfrac{1\cancel{sin(\theta)}+1\cancel{+sin(\theta)}}{{\color{brown}{ [1^2sin^2(\theta)] }}}\implies \cfrac{2}{{\color{brown}{ cos^2(\theta)}}} \\ \quad \\ 2\cdot \cfrac{1}{cos^2(\theta)}\implies 2sec^2(\theta)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the denominator is combined, since it's just a difference of squares and keep in mind that \(\bf sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)={\color{brown}{ 1cos^2(\theta)}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0woops, darn that came out off lemme redo that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)={\color{brown}{ 1sin^2(\theta)}}\) rather
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