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wintersuntime

  • one year ago

Can someone be nice enough to help me with this problem please -> 3/4x+1/2=3/2

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  1. wintersuntime
    • one year ago
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    x=4/3

  2. jdoe0001
    • one year ago
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    hint: multiply both sides by "4x"

  3. wintersuntime
    • one year ago
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    they are all fractions

  4. wintersuntime
    • one year ago
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    @sebaxtiangb

  5. jdoe0001
    • one year ago
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    right... thus multiplying them by 4x, removes the denominator and you'd end up with numerators

  6. jdoe0001
    • one year ago
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    \(\bf \cancel{4x}\cdot \cfrac{3}{\cancel{4x}}+\cancel{4} x\cdot \cfrac{1}{\cancel{2}}=\cancel{4}x\cdot \cfrac{3}{\cancel{2}}\implies ?\)

  7. anonymous
    • one year ago
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    Subtract 1/2 on both sides first.

  8. jdoe0001
    • one year ago
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    \(\bf \cancel{4x}\cdot \cfrac{3}{\cancel{4x}}+\cancel{4} x\cdot \cfrac{1}{\cancel{2}}=\cancel{4}x\cdot \cfrac{3}{\cancel{2}}\implies 3+2x\cdot 1=2x\cdot 3 \\ \quad \\ 3+2x=6x\implies ?\)

  9. anonymous
    • one year ago
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    |dw:1438733335459:dw| Then subtract the terms on the right sides. You can even simplify it.

  10. anonymous
    • one year ago
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    |dw:1438733426348:dw| Then multiply the reciprocal of 3/4 (which is 4/3) on both sides. That's it.

  11. wintersuntime
    • one year ago
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    @jdoe0001

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