Abel uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below: Number on the Cube Number of Times Rolled 1 12 2 18 3 30 4 22 5 10 6 8 Heads Tails 34 66 Using Abel's simulation, what is the probability of rolling a 2 on the number cube and the coin landing on tails? fraction 84 over 10,000 fraction 1,188 over 10,000 fraction 18 over 100 fraction 66 over 100

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Abel uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below: Number on the Cube Number of Times Rolled 1 12 2 18 3 30 4 22 5 10 6 8 Heads Tails 34 66 Using Abel's simulation, what is the probability of rolling a 2 on the number cube and the coin landing on tails? fraction 84 over 10,000 fraction 1,188 over 10,000 fraction 18 over 100 fraction 66 over 100

Mathematics
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can i get help by help step
@Mertsj can you help
Probability of A and B for independent events is P(A) x P(B)

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36*66?
2376/2 = 1188? @Mertsj
What is the probability of a 2?
100/2?
am i on the right track
@kropot72 am i on the right
The probability of rolling a 2 is given by: \[\large P(2)=\frac{number\ of\ 2s\ rolled}{total\ rolls}\]
1188/10000 @kropot72
@steffie84 How did you get that?
66*34/2*100*100
Not really. What is the probability of rolling a 2 (using the equation in my first post here)?
total roll is 100?
@kropot72 am not sure what
The number 2 came up 18 times in a total of 100 rolls.
@kropot72 just saw what you are talking about
18/100
Correct. The probability of tails is found from: \[\large P(tails)=\frac{number\ of\ tails}{total\ flips}\]
66/100
Correct again. Therefore as @Mertsj told you, the required probability is given by: \[\frac{18}{100}\times\frac{66}{100}=you\ can\ calculate\] Hint: Do not simplify the result of your calculation.
1188
10000
So the result is \[\large \frac{1188}{10000}\]
yes
You're welcome :)

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