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anonymous

  • one year ago

Abel uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below: Number on the Cube Number of Times Rolled 1 12 2 18 3 30 4 22 5 10 6 8 Heads Tails 34 66 Using Abel's simulation, what is the probability of rolling a 2 on the number cube and the coin landing on tails? fraction 84 over 10,000 fraction 1,188 over 10,000 fraction 18 over 100 fraction 66 over 100

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  1. anonymous
    • one year ago
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    can i get help by help step

  2. anonymous
    • one year ago
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    @Mertsj can you help

  3. Mertsj
    • one year ago
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    Probability of A and B for independent events is P(A) x P(B)

  4. anonymous
    • one year ago
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    36*66?

  5. anonymous
    • one year ago
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    2376/2 = 1188? @Mertsj

  6. Mertsj
    • one year ago
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    What is the probability of a 2?

  7. anonymous
    • one year ago
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    100/2?

  8. anonymous
    • one year ago
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    @Mertsj

  9. anonymous
    • one year ago
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    am i on the right track

  10. anonymous
    • one year ago
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    @kropot72 am i on the right

  11. kropot72
    • one year ago
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    The probability of rolling a 2 is given by: \[\large P(2)=\frac{number\ of\ 2s\ rolled}{total\ rolls}\]

  12. anonymous
    • one year ago
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    ok @kropot72

  13. anonymous
    • one year ago
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    1188/10000 @kropot72

  14. kropot72
    • one year ago
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    @steffie84 How did you get that?

  15. anonymous
    • one year ago
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    66*34/2*100*100

  16. anonymous
    • one year ago
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    @kropot72

  17. kropot72
    • one year ago
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    Not really. What is the probability of rolling a 2 (using the equation in my first post here)?

  18. anonymous
    • one year ago
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    total roll is 100?

  19. anonymous
    • one year ago
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    @kropot72 am not sure what

  20. kropot72
    • one year ago
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    The number 2 came up 18 times in a total of 100 rolls.

  21. anonymous
    • one year ago
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    @kropot72 just saw what you are talking about

  22. anonymous
    • one year ago
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    18/100

  23. kropot72
    • one year ago
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    Correct. The probability of tails is found from: \[\large P(tails)=\frac{number\ of\ tails}{total\ flips}\]

  24. anonymous
    • one year ago
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    66/100

  25. kropot72
    • one year ago
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    Correct again. Therefore as @Mertsj told you, the required probability is given by: \[\frac{18}{100}\times\frac{66}{100}=you\ can\ calculate\] Hint: Do not simplify the result of your calculation.

  26. anonymous
    • one year ago
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    1188

  27. anonymous
    • one year ago
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    10000

  28. kropot72
    • one year ago
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    So the result is \[\large \frac{1188}{10000}\]

  29. anonymous
    • one year ago
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    yes

  30. anonymous
    • one year ago
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    @kropot72 @Mertsj thanks

  31. kropot72
    • one year ago
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    You're welcome :)

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