## anonymous one year ago Abel uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below: Number on the Cube Number of Times Rolled 1 12 2 18 3 30 4 22 5 10 6 8 Heads Tails 34 66 Using Abel's simulation, what is the probability of rolling a 2 on the number cube and the coin landing on tails? fraction 84 over 10,000 fraction 1,188 over 10,000 fraction 18 over 100 fraction 66 over 100

1. anonymous

can i get help by help step

2. anonymous

@Mertsj can you help

3. Mertsj

Probability of A and B for independent events is P(A) x P(B)

4. anonymous

36*66?

5. anonymous

2376/2 = 1188? @Mertsj

6. Mertsj

What is the probability of a 2?

7. anonymous

100/2?

8. anonymous

@Mertsj

9. anonymous

am i on the right track

10. anonymous

@kropot72 am i on the right

11. kropot72

The probability of rolling a 2 is given by: $\large P(2)=\frac{number\ of\ 2s\ rolled}{total\ rolls}$

12. anonymous

ok @kropot72

13. anonymous

1188/10000 @kropot72

14. kropot72

@steffie84 How did you get that?

15. anonymous

66*34/2*100*100

16. anonymous

@kropot72

17. kropot72

Not really. What is the probability of rolling a 2 (using the equation in my first post here)?

18. anonymous

total roll is 100?

19. anonymous

@kropot72 am not sure what

20. kropot72

The number 2 came up 18 times in a total of 100 rolls.

21. anonymous

@kropot72 just saw what you are talking about

22. anonymous

18/100

23. kropot72

Correct. The probability of tails is found from: $\large P(tails)=\frac{number\ of\ tails}{total\ flips}$

24. anonymous

66/100

25. kropot72

Correct again. Therefore as @Mertsj told you, the required probability is given by: $\frac{18}{100}\times\frac{66}{100}=you\ can\ calculate$ Hint: Do not simplify the result of your calculation.

26. anonymous

1188

27. anonymous

10000

28. kropot72

So the result is $\large \frac{1188}{10000}$

29. anonymous

yes

30. anonymous

@kropot72 @Mertsj thanks

31. kropot72

You're welcome :)