anonymous
  • anonymous
FLVS BLOWS SOMEONE PLEASE EXPLAIN THIS TOO MEEEE!! What is the simplified form of the quantity of x plus 4, all over the quantity of 7 − the quantity of x plus 3, all over the quantity of x plus 5? (I will re-write with numbers shortly)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1438737500786:dw|
anonymous
  • anonymous
I know you need to make the denominator the same I got this far...|dw:1438737614751:dw|
phi
  • phi
I would leave the bottom 7(x+5) but if you do multiply it out (i.e. distribute the 7) you get 7x+35 (not 7x+30)

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anonymous
  • anonymous
Oh ok thanks so any idea how to subtract (x-3) from two binomials being multiplied together?
phi
  • phi
also, the 2nd fraction should have been multiplied by 7/7 it should look like this \[ \frac{(x+4)(x+5)- 7(x+3)}{7(x+5)} \] now use FOIL to multiply (x+4)(x+5) up top also distribute the -7.... you get -7x-21
anonymous
  • anonymous
I HATE FLVS 2!!!
anonymous
  • anonymous
x^2+9x+20-7x+21/7(x+5)
anonymous
  • anonymous
-21*
phi
  • phi
now combine "like terms"
anonymous
  • anonymous
omg I got one of the answers ty sooo much!!! (so much better then flvs)
phi
  • phi
It really isn't "simplified form" (whatever that means) but it is one fraction.

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