anonymous
  • anonymous
Use the given conditions to write an equation for the line in point-slope form. Passing through (-5, -7) and (-8, -6)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I get -2x + -2y = 26 and that is not one of my choices
DecentNabeel
  • DecentNabeel
first find the slope.. do you find the slope
anonymous
  • anonymous
0.3?

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anonymous
  • anonymous
Im sorry but im getting -2,-2
anonymous
  • anonymous
so would the slope be 0?
DecentNabeel
  • DecentNabeel
slope=y2-y1/(x2-x1) the point is the given (-5,-7)(-8,-6) x1=-5 y1=-7 x2=-8 y2=-6 plug in .. slope=m=(-6+7)/(-8+5) m=-1/3
anonymous
  • anonymous
I apologize but im still not understanding
DecentNabeel
  • DecentNabeel
do you point slope formula..
anonymous
  • anonymous
y - y1 = m(x - x1)
DecentNabeel
  • DecentNabeel
slope=m m=(y2-y1)/(x2-x1)
DecentNabeel
  • DecentNabeel
ok.. first find the slope
anonymous
  • anonymous
-1/3
DecentNabeel
  • DecentNabeel
m=-1/3 so use the point (-5,-7) x1=-5 y1=-7 y - y1 = m(x - x1 y+7=(-1/3)(x+5) \[y+7=-\frac{1}{3}x-\frac{5}{3}\]
DecentNabeel
  • DecentNabeel
yes good slope =-1/3
anonymous
  • anonymous
y + 7 = -1/3 x - 5 or y + 6 = -1/3 x + 7 this is the answer I got after plugging everything in
DecentNabeel
  • DecentNabeel
y + 7 = -1/3 x - 5/3 not only 5
DecentNabeel
  • DecentNabeel
\[y+6=-\frac{1}{3}\left(x+5\right)\] -1/3 multiple for both x and 5
anonymous
  • anonymous
I got it thnk you for all your help

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