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anonymous
 one year ago
Find the between graphs of y=x^2+2 and y=1x between x=0 and x=1. Can you guys please check if my equation is right, I will type it below.
anonymous
 one year ago
Find the between graphs of y=x^2+2 and y=1x between x=0 and x=1. Can you guys please check if my equation is right, I will type it below.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0parabola is above the line, not below it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooopsss I think my drawing is wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438743560886:dw i thought this is like this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not if it is \(y=x^2+2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0upper strip  lower strip right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=x^2%2B2%2C1x+domain+0..1

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1You had y=x^2+2, the parabola is shifted up to 2 units Yes, i graphed mines a little off dw:1438743695117:dw

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1When you major the rectangle, the top graph is the parabola y=x^2+2 and the bottom of the rectangle is the line graph y=1x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Soooo it is [(x^2+2)(1x)]

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{a}^{b}(Y(x)y(x))dx\]

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1The limits of the integral are x=0 and x=1 So a=0 and b=1 Y=x^2+2 and y=1x So: \[\int\limits_{0}^{1} [(x^2+2)(1x)]dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[[x^2+x1]\] then this?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1You integrate\[\int\limits_{0}^{1}[x^2+x+1]dx\]

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1No because your integral is not correct due to not distributing appropriately.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for your help!! Hoping you can help me sometimes again. Thankyou!

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1It was good to work with you!
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