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anonymous

  • one year ago

what is the radius? x^2+y^2-2x+6y+9=0

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  1. anonymous
    • one year ago
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    \[\sqrt{9}=?\]

  2. UsukiDoll
    • one year ago
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    maybe it helps to rearrange this equation first and then have it in the equation of the circle format.

  3. freckles
    • one year ago
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    completing the square needs to be done for the x and y terms separately of course

  4. UsukiDoll
    • one year ago
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    OH right forgot that @freckles

  5. anonymous
    • one year ago
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    oh yes.

  6. anonymous
    • one year ago
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    the answer is 1 thank you all though :)

  7. UsukiDoll
    • one year ago
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    how did you get 1?

  8. anonymous
    • one year ago
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    graphing calculator perhaps

  9. UsukiDoll
    • one year ago
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    or desmos/wolfram alpha XDDDDDDDDDDDDD

  10. anonymous
    • one year ago
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    \[(x^2-2x)+(y^2+6y)=-9\]

  11. anonymous
    • one year ago
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    i didnt but i got answer wrong and the test said the correct anwer was 1 lol

  12. anonymous
    • one year ago
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    thats why we never get mcq for test

  13. UsukiDoll
    • one year ago
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    <_< yeah that's why I asked... you need to understand the concepts of this so you can be able to solve these equations

  14. UsukiDoll
    • one year ago
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    mcq? @saseal

  15. anonymous
    • one year ago
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    multiple choice questions

  16. UsukiDoll
    • one year ago
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    oh XD. Come to think of it, it's been years since I had one

  17. anonymous
    • one year ago
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    @grecar98 take that equation i gave ya and complete the square

  18. anonymous
    • one year ago
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    time for me to learn bitumen road making...afk!

  19. IrishBoy123
    • one year ago
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    as the OP has found the answer: \(x^2+y^2-2x+6y+9=0\) rearrange \(x^2 - 2x +y^2+6y+9=0\) complete squares \([(x-1)^2 -1] +[(y +3)^2 - 9] +9=0\)

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