anonymous
  • anonymous
What is the most optimal way of solving these kinds of problems? 3x - 2y = 5 4x + y = 14 https://i.imgur.com/puhf2Vo.png
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Originally I thought there was an ordered pair or 5, 5, but that won't work for the second equation.
midhun.madhu1987
  • midhun.madhu1987
3x - 2y = 5 -----(1) 4x + y = 14 -----(2) We need to make the coefficients for any variable equal(x or y). So, if we multiply equation (2) by 2 , then both equations will have same coefficients of y. Then just add both equations.. and y will be eliminated and x can be found.
anonymous
  • anonymous
3x - 2y = 5 8x + 2y = 28 then we add them to be 11x + 0y =33

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UsukiDoll
  • UsukiDoll
you don't have to write 0y just 11x = 33 and then divide 11 on both sides.
anonymous
  • anonymous
That gives me x = 3, but that wouldn't be an ordered pair. Entering that back into the original equations won't work.
UsukiDoll
  • UsukiDoll
did you solve for y?
UsukiDoll
  • UsukiDoll
4x + y = 14 plug x = 3 back in this equation and solve for y
anonymous
  • anonymous
12 + y = 14 -12 on both sides y = 2 okay, then the pair is 3,2.
UsukiDoll
  • UsukiDoll
because right now you have (3, ?) we need y ... yes (3,2)
anonymous
  • anonymous
That still doesn't work if you put them into 3x-2y = 5.
UsukiDoll
  • UsukiDoll
not true 3(3) - 2(2) = 5 9-4=5 5=5
UsukiDoll
  • UsukiDoll
4x + y = 14 4(3)+2=14 12+2=14 14=14 it works
anonymous
  • anonymous
oh wait, I accidentally put in 3(2) and - 2(3)
anonymous
  • anonymous
You're correct, I'm, just a doof.
UsukiDoll
  • UsukiDoll
take a break from math... that's where mistakes pop up... by over doing them.
anonymous
  • anonymous
I'm gonna do that now, thanks for all the help! :)

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