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anonymous
 one year ago
A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball can be modeled by h(t) = 16t2 + 50t + 6, where t is the time in seconds since the ball was thrown. It takes the ball approximately _____ seconds to reach its maximum height. (Round to the nearest tenth of a second and enter only the number.)
anonymous
 one year ago
A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball can be modeled by h(t) = 16t2 + 50t + 6, where t is the time in seconds since the ball was thrown. It takes the ball approximately _____ seconds to reach its maximum height. (Round to the nearest tenth of a second and enter only the number.)

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Zale101
 one year ago
Best ResponseYou've already chosen the best response.0When you are looking at the highest point that object reached to, you'd have to consider the vertex. The vertex can be the min or the max in a parabola (quadratic equation). But since we threw in object, our parabola is an upside down parabola. Hence your equation h(t) = 16t2 + 50t + 6, the quadratic equation is negative because it is an upside down parabola. dw:1438759954750:dw

Zale101
 one year ago
Best ResponseYou've already chosen the best response.0Do you remember the process of finding the vertex of a parabola? You complete the square or use the vertex formula to find the vertex of a given standard equation like h(t) = 16t2 + 50t + 6. Do you remember on how to do any of this?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.0Since we are dealing with an upside down parabola, our vertex is the global maximum of the function.
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