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anonymous

  • one year ago

Please help! (Photo In Replies)

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @conain007

  3. Astrophysics
    • one year ago
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    |dw:1438763247834:dw| \[V = l w h\]

  4. anonymous
    • one year ago
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    ...

  5. anonymous
    • one year ago
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    can you write out the problem

  6. Astrophysics
    • one year ago
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    Just multiply it

  7. Astrophysics
    • one year ago
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    That's all it's asking so we have \[V = (2x^2)(2x^3)(5x)\]

  8. Astrophysics
    • one year ago
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    \[x^n x^m = x^{n+m}\]

  9. Astrophysics
    • one year ago
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    When you multiply exponents you just add them

  10. anonymous
    • one year ago
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    oh i got it. its like 160 rite

  11. anonymous
    • one year ago
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    so its like 10^6

  12. Astrophysics
    • one year ago
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    Mhm not quite, what is 2 *2*5

  13. Astrophysics
    • one year ago
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    Yeah the exponent is right :)

  14. anonymous
    • one year ago
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    so its like b because 10^6

  15. Astrophysics
    • one year ago
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    No, remember we have \[2 \times 2 \times 5 = 20\]

  16. Astrophysics
    • one year ago
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    Ok look \[V = (2x^2)(2x^3)(5x) = (2 \times 2 \times 5)(x^6)\]

  17. Astrophysics
    • one year ago
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    Yeah :)

  18. Astrophysics
    • one year ago
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    But I see you're getting the idea, that's good!

  19. Astrophysics
    • one year ago
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    You had the exponents right but you forgot to multiply by another 2, so we have \[20x^6\]

  20. Astrophysics
    • one year ago
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    Does it make sense now?

  21. anonymous
    • one year ago
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    so wait wat. whats the anser now

  22. anonymous
    • one year ago
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    hello

  23. Astrophysics
    • one year ago
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    What?

  24. anonymous
    • one year ago
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    thanks lol

  25. Astrophysics
    • one year ago
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    lol

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