Help? I'm stuck. Applications of Quadratic Applications.

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Help? I'm stuck. Applications of Quadratic Applications.

Mathematics
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\[S=-16t^2+11t\] \[(-1)0= (-1)(-16t^2+112 t)\] \[0=16t^2-112t\] That is what I got. I've tried solving further but I'm confused...
what r u tryin to figure out
Well, now I'm supposed to be factoring the last equation...

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Other answers:

try completing the square
You could use the quadratic equation if you like, c = 0, or complete the square.
itll be in the form (a-b)(a+b)
Yes, I do know that I just do not know how to go from what I've put up last.
just take any random number, plug it in and see what happens i guess lol
You could just do (11-16t)t=0 that gives your factors
factoring out a t
Nevermind I got it haha. Thanks guys!
Ok :)
\[16t^2-112t+(\frac{ 112 }{ 2 })^2= (\frac{ 112 }{ 2 })^2\]
lol ok
S = -16t^2+11t is different from 16t^2-112t, I'm assuming there was just a mistake there, but you can do the same as above for it in any case, I guess you realized that :P

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